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kupik [55]
3 years ago
13

What is differnt between reactance and inped ance?

Physics
1 answer:
stellarik [79]3 years ago
6 0
Impedance is basically the overall resistance/impeding factor against a current in an electrical circuit. Inductive and capacitive reactances are used in a formula to DETERMINE impedance (it uses resistance too) and they are basically the opposition towards a current caused by the inductor (ex. coil) and a capacitor, respectively, in an LC or RLC circuit.
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A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130
konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(c) W = 0J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

W=Fd      (1)

F: applied force = 130N

d: distance = 5.0m

W=(130N)(5.0m)=650J

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

W_f=F_fd=\mu Mgd       (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

W = 0J

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

\Delta K=W_T         (3)

You calculate the total work:

W_T=Fd-F_fd=(F-F_f)d     (4)

F: applied force = 130N

Ff: friction force

d: distance = 5.00m

The friction force is:

F_f=(0.300)(36.0kg)(9.8m/s^2)=105.84N

Next, you replace the values of all parameters in the equation (4):

W_T=(130N-105.84N)(5.00m)=120.80J

\Delta K=120.80J

The change in the kinetic energy of the box is 120.8J

(e) The final speed of the box is calculated by using the equation (3):

W_T=\frac{1}{2}M(v_2^2-v_1^2)       (5)

v2: final speed of the box

v1: initial speed of the box = 0 m/s

You solve the equation (5) for v2:

v_2 = \sqrt{\frac{2W_T}{M}}=\sqrt{\frac{2(120.8J)}{36.0kg}}=2.58\frac{m}{s}

The final speed of the box is 2.58m/s

5 0
3 years ago
what is the relationship between the evolution of marsupials and the movement of earths tectonic plate? 8th Grade No links or fi
svetlana [45]
Both require long periods of time to occur (possibly hundreds of years I think)
8 0
3 years ago
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laila [671]

Answer:

d

Explanation:

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2 years ago
Name your favorite color.
Arisa [49]

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Light blue

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A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
mr Goodwill [35]

Answer:

+17 kg m/s

Explanation:

Question is missing. Found it on google:

"<em>What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg</em>?"

Solution:

we can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved, so we can write:

p_i = p_f\\p_b+p_p=p_b'+p_p'

where

p_b = +30 kg m/s is the momentum of the ball before the collision

p_p = 0 is the momentum of the pin before the collision (zero because the pin is stationary)

p_b' = +13 kg m/s is the momentum of the ball after the collision

p_p' is the momentum of the pin after the collision

Solving the equation for p_p', we find:

p_p' = p_b + p_p - p_b' = +30 +0 -(+13)=+17 kg m/s

4 0
3 years ago
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