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aleksandrvk [35]
3 years ago
11

Which of the following is a potential result of preparing appropriately before starting an experiment in a lab?

Physics
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:

Your project goes well.

Explanation:

Because that's how it works.

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An aluminum bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 40mm in diameter and 10
s2008m [1.1K]

Answer:

<em>1.228 x </em>10^{-6}<em> mm </em>

<em></em>

Explanation:

diameter of aluminium bar D = 40 mm  

diameter of hole d = 30 mm

compressive Load F = 180 kN = 180 x 10^{3} N

modulus of elasticity E = 85 GN/m^2  = 85 x 10^{9} Pa

length of bar L = 600 mm

length of hole = 100 mm

true length of bar = 600 - 100 = 500 mm

area of the bar A = \frac{\pi D^{2} }{4} =  \frac{3.142* 40^{2} }{4} = 1256.8 mm^2

area of hole a = \frac{\pi(D^{2} - d^{2}) }{4} = \frac{3.142*(40^{2} - 30^{2})}{4} = 549.85 mm^2

Total contraction of the bar = \frac{F*L}{AE} + \frac{Fl}{aE}

total contraction = \frac{F}{E} * (\frac{L}{A} +\frac{l}{a})

==> \frac{180*10^{3}}{85*10^{9}} *( \frac{500}{1256.8} + \frac{100}{549.85}) = <em>1.228 x </em>10^{-6}<em> mm </em>

6 0
3 years ago
Garrett Hardin's "Tragedy of the Commons" describes the tendency of people to overuse publicly-owned natural resources until the
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Answer:

is it bad if i keep thinking about p ussy

Explanation:

8 0
3 years ago
A wave with a high frequency generally has a _____.
il63 [147K]
High frequency = D, short wavelength
4 0
3 years ago
Which of the following correctly describes the importance of demonstrations to scientific investigation?
sergey [27]

Answer:

A- A demonstration shows how something works, often including models

Explanation:

A demonstration allows, through experimentation, to show how nature works and in that way can include the explanation of scientific theories that explain the set of observed facts, that is, it serves as a demonstration of the underlying scientific principles.

5 0
3 years ago
Two loudspeakers emit 600 Hz Hz notes. One speaker sits on the ground. The other speaker is in the back of a pickup truck. You h
Firdavs [7]

Answer:

The truck's speed is 4.04 m/s.

Explanation:

Given that,

Emit frequency = 600 Hz

Beat = 7.00 beat/sec

We need to calculate the truck's speed

Using formula of speed

\text{frequency observed}=\text{frequency emitted}\times\dfrac{v}{v+v_{source}}

Where, v = speed of sound

Put the value into the formula

(600-7)=600\times(\dfrac{343}{343-v_{truck}})

v_{truck}=\dfrac{600\times343-593\times343}{593}

v_{truck}=4.04\ m/s

Hence, The truck's speed is 4.04 m/s.

3 0
3 years ago
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