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Zanzabum
3 years ago
12

B. A guitar string has a length of 0.90 m. When you pluck it, it plays a “C” that has a frequency of 256 Hz. How fast is the wav

e moving back and forth along the string? (Choose one of the equations from the box at the top of the page to solve this problem.)
Equations to use: v= λ ∙ f v=d/t
Physics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

461  m/s

Explanation:

Given the string length of guitar, l = 0.90 m

Frequency , f = 256 Hz

Using frequency, wavelength and velocity relation as

v=f λ

Here λ is wavelength.

Now for guitar string the length must be equal to half of wavelength, so

λ = 2l

Therefor above formula becomes as  

v = f×2l

Substituting the given values, we get

v =256×2×0.90

v = 460.8 m/s = 461 m/s

Thus, the wave moving back and forth along the string with velocity 461 m/s.

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A brave child decides to grab onto an already spinning merry‑go‑round. The child is initially at rest and has a mass of 34.5 kg.
ozzi

Answer:

I_1 = 32.5 kg m^2

Explanation:

Here as we know that total angular momentum is always conserved for child + round system

so here by angular momentum conservation we have

I_1 \omega_1 = (I_1 + I_2)\omega_2

here we have

I_2 = mR^2 (inertia of boy)

I_2 = (34.5)(1.45^2)

I_2 = 72.5 kg m^2

now we have

I_1(2\pi 55) = (I_1 + 72.5)(2 \pi 17)

I_1 = (I_1 + 72.5)(0.31)

I_1(1 - 0.31) = 22.4

I_1 = 32.5 kg m^2

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3 years ago
The time needed for a wave to make one complete cycle is its
posledela
<span>The time needed for a wave to make one complete cycle is its period.</span>
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3 4 5 plz I really need it thanks
Kay [80]
3. A chemical symbol designates an element that belongs to the periodic table. A chemical formula combines two or more symbols and it represents a chemical compound. 4.A mixture is made of two or more substances—elements, compounds, or both—that are together in the same place but are not chemically combined. Example: vegetable soup!Mixtures differ from compounds intwo ways: Each substance in a mixturekeeps its individual properties. 5.filtration, evaporation, distillation, chromatography
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How come that there is a presence of cos there?
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8 0
3 years ago
The electrons in the beam of a television tube have a kinetic energy of 2.20 10-15 j. initially, the electrons move horizontally
dalvyx [7]
(a) The electrons move horizontally from west to east, while the magnetic field is directed downward, toward the surface. We can determine the direction of the force on the electron by using the right-hand rule:
- index finger: velocity --> due east
- middle finger: magnetic field --> downward
- thumb: force --> due north
However, we have to take into account that the electron has negative charge, therefore we have to take the opposite direction: so, the magnetic force is directed southwards, and the electrons are deflected due south.

b) From the kinetic energy of the electrons, we can find their velocity by using
K= \frac{1}{2}mv^2
where K is the kinetic energy, m the electron mass and v their velocity. Re-arranging the formula, we find
v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 2.20 \cdot 10^{-15} J}{9.1 \cdot 10^{-31} kg} }=6.95 \cdot 10^7 m/s

The Lorentz force due to the magnetic field provides the centripetal force that deflects the electrons:
qvB = m \frac{v^2}{r}
where
q is the electron charge
v is the speed
B is the magnetic field strength
m is the electron mass
r is the radius of the trajectory
By re-arranging the equation, we find the radius r:
r= \frac{mv}{qB}= \frac{(9.1 \cdot 10^{-31} kg)(6.95 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19} C)(3.00 \cdot 10^{-5} T)}=13.18 m

And finally we can calculate the centripetal acceleration, given by:
a_c =  \frac{v^2}{r}= \frac{(6.95 \cdot 10^7 m/s)^2}{13.18 m}=3.66 \cdot 10^{14} m/s^2
5 0
3 years ago
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