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2 years ago

Can someone help me and give me the right answer

Physics

2 answers:

Lera25 [3.4K]2 years ago

8 0

Answer:

C. sedimentary

Explanation:

FrozenT [24]2 years ago

5 0

Answer:

Sedimentary

Explanation:

Igneous rock- A rock that's formed through the cooling and solidification of magma or lava.

Metamorphic rock- A rock that starts out as another rock and often has a striped appearance.

Volcanic rock- A rock that's formed from lava that erupted from a volcano.

Sedimentary is the only right answer. A Sedimentary rock is a rock thats made from the deposition of lots of pieces of eroded rock particles.

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Airbags and safety belts can reduce injuries because they can

pashok25 [27]

Answer:

reduce the velocity of collision

5 0

3 years ago

Is everyone in your class able to hear a quiet sound equally well?

Sergio039 [100]

Answer:

Explanation:

Loudness describes how people perceive sound (see loudness). ... If people could hear equally well at all frequencies, the contour lines would be flat because the same measured sound intensity would be perceived to be equally loud regardless of the sound frequency. In fact, people do not hear as well at low frequencies.

8 0

3 years ago

A lowly high diver pushes off horizontally with a speed of 2.00 m/s from the platform edge 10.0 m above the surface of the water

VladimirAG [237]

Answer:

(a) 1.6m

(b) 6.86m

Explanation:

This is a horizontal shooting problem, so we will use the following equations.

For horizontal distance x we use:

$x(t)=x_{0}+v_{0}t$

Where $x(t)$ is the horizontal distance at a time $t$ , $x_{0}$ is the initial horizontal position which in this case will be zero: $x_{0}=0$ . And $v_{0}$ is the initial speed: $v_{0}=2m/s$

So to solve (a):

(a) At what horizontal distance from the edge is the diver 0.800 s after pushing off?

we have that the time is: $t=0.8s$ so the horizontal distance is:

$x(0.8)=(2m/s)(0.8s)1.6m$

<u>The answer for (a) is 1.6m</u>

Now, to solve (b) we need the equation for vertical distance:

$y(t)=y_{0}-\frac{1}{2}gt^2$

Where $y(t)$ is the vertical distance at a time $t$ , $y_{0}$ is the initial vertical distance: $y_{0}=10m$ And $g$ is the gravitational acceleration: $g=9.81m/s^2$ }

(b) At what vertical distance above the surface of the water is the diver just then?

The time is the same as in the last question: $t=0.8s$

$y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.8)^2$

$y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.64s^2)$

$y(0.8)=10m-\frac{1}{2}(6.2784m)$

$y(0.8)=10m-(3.1392)$

$y(0.8)=6.86m$

<u>the answer to (b) is 6.86m</u>

(c) At what horizontal distance from the edge does the diver strike the water?

To solve (c) we first need to know how long it took to reach the height of the water, that is, for what time y = 0

Using $y(t)=y_{0}-\frac{1}{2}gt^2$

if $y(t)=0$

$0=10-\frac{1}{2}gt^2\\-10=-\frac{1}{2}gt^2\\20=gt^2\\\frac{20}{g}=t^2\\ \sqrt{\frac{20}{g}}=t$

and since $g=9.81m/s^2$

$t=\sqrt{\frac{20}{9.81} } =\sqrt{2.039}=1.43s$

At $t=1.43s$ the car hits the water, so the horizontal distance at that time is:

$x(t)=x_{0}+v_{0}t$

$x(1.43)=(2m/s)(1.43s)=2.86m$

<u>the answer to (c) is 2.86s</u>

6 0

3 years ago

Can it is possible to complete half syllabus of physics class 11 in 8 days?

castortr0y [4]

Answer:

In the human thoughts, there is possible and impossible. In God's world everything is possible. If you keep thinking this you'll never start to study. Just get up, open the book and start to study like you do. Believe in yourself!

3 0

3 years ago

Your friend, Tim, is playing with his sled. He ties a rope to his sled and attaches it to Lar's snowmobile. Tim has a mass of 71

kykrilka [37]

The maximum speed of Tim is 16.95 m/s.

The given parameters:

Mass of the rope, m = 71 kg
Tension on the rope, T = 220 N
Coefficient of kinetic friction, = 0.1
Time of motion, t = 8 s

<h3>What is Newton's second law of motion?</h3>

Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on Tim is calculated by applying Newton's second law of motion as follows;

$T - \mu _k F_n = ma\\\\T - \mu _k F_n = m\frac{v}{t} \\\\T - \mu_k mg = m\frac{v}{t} \\\\t(\frac{T - \mu_k mg}{m} )= v\\\\8 (\frac{220 \ -\ 0.1 \times 71 \times 9.8}{71} ) =v \\\\ 16.95 \ m/s = v$

Thus, the maximum speed of Tim is 16.95 m/s.

Learn more about net horizontal force here: brainly.com/question/21684583

7 0

3 years ago