Answer:
The answer is below
Explanation:
Plants that grow among many tall trees in a dense forest could adapt so that they could get enough air and water through the following means:
1. By becoming climbers. Here they climb up the nearby trees to get more air and sunlight.
2. Plants grow leaves that have pointed tips. This allows the passage of water in the plant's leaves without causing damage.
3. Some plants grow as epiphytes, where they grow on big trees' canopy
Answer:
The acceleration of the object is 9.3 m/s²
Explanation:
For a straight movement with constant acceleration, this equation for the position applies:
x = x0 + v0 t + 1/2 a t²
where
x = position at time t
x0 = initial position
v0 = initial velocity
a = acceleration
t = time
we have two positions: one at time t = 1 s and one at time t = 2 s. We know that the difference between these positions is 14.0 m. These are the equations we can use to obtain the acceleration:
x₁ = x0 + v0 t + 1/2 a (1 s)²
x₂ = x0 + v0 t + 1/2 a (2 s)²
x₂ - x₁ = 14 m
we know that the object starts from rest, so v0 = 0
substracting both equations of position we will get:
x₂ - x₁ = 14
x0 + v0 t + 1/2 a (2 s)² - (x0 + v0 t + 1/2 a (1 s)²) = 14 m
x0 + v0 t + 2 a s² - x0 -v0 t - 1/2 a s² = 14 m
2 a s² - 1/2 a s² = 14 m
3/2 a s² = 14 m
a = 14 m / (3/2 s²) = <u>9.3 m/s² </u>
Answer:
ΔL = 5.09x10^-5 m
Explanation:
data provided by the exercise:
m = 56 kg
L = 35 cm = 0.35 m
r = 1.5 cm = 0.015 m
Y = 1.6x10^10 N/m^2
F = 3 m*g
A = pi*r^2
The Young´s modulus is equal to:
Y = (F/A)/(ΔL/L) = (F*L)/(A*ΔL)
Clearing ΔL, we have:
ΔL = (F*L)/(A*Y) = (3*56*9.8*0.35)/(pi*(0.015^2)*1.6x10^10) = 5.09x10^-5 m