Answer: l = 2142.8575 ft
v = 193.99 ft/min.
Explanation:
Given data:
Thickness of the slab = 3in
Length of the slab = 15ft
Width of the slab = 10in
Speed of the slab = 40ft/min
Solution:
a. After three phase
three phase = (0.2)(0.2)(0.2)(3.0)
= 0.024in.
wf = (1.03)(1.03)(1.03)(10.0)
= 10.927 in.
Using constant volume formula
= (3.0)(10.0)(15 x 15) = (0.024)(10.927)Lf
Lf = (3.0)(10.0)(15 x 15)/(0.024)(10.927)
= 6750 /0.2625
= 25714.28in = 2142.8575 ft
b.
vf = (0.2 x 0.2 x 3.0)(1.03 x 1.03 x 10.0)(40)/(0.024)(10.927)
= (0.12)(424.36)/0.2625
= 50.9232/0.2625
= 193.99 ft/min.
Answer:
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Explanation:
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Answer:
Example for strengthening mechanism in single-phase material: Strain hardening- D.
Answer:
the minimum expected elastic modulus is 372.27 Gpa
Explanation:
First we put down the data in the given question;
Volume fraction
= 0.84
Volume fraction of matrix material
= 1 - 0.84 = 0.16
Elastic module of particle
= 682 GPa
Elastic module of matrix material
= 110 GPa
Now, the minimum expected elastic modulus will be;
= (
×
) / ( 
+
)
so we substitute in our values
= (682 × 110 ) / ( [ 682 × 0.16 ] + [ 110 × 0.84] )
= ( 75,020 ) / ( 109.12 + 92.4 )
= 75,020 / 201.52
= 372.27 Gpa
Therefore, the minimum expected elastic modulus is 372.27 Gpa
Answer:
the relation between load , shear force and bending moment is
shear force in a beam is calculated by the differentiation of the loading with respect to distance or length of the beam

Bending moment in a beam is define as the change of shear force diagram with respect to the length of the beam.

and where as
where V is the shear force , x is the distance in the beam , M is the bending moment and w is the loading on the beam.