Answer:
The correct answer to the following question will be "Because the head acts as a stop".
Explanation:
- Since the head serves as either a stopping (especially in comparison to something like a floppy tape clip or hanger), the combination square seems to be more reliable and accurate than those of the tape measure.
- And maybe you'll know that certain style outlines are still square to something like the sides or finishes.
So that the above seems to be the right answer.
Answer:
The time required to elute the two species is 53.3727 min
Explanation:
Given data:
tA = retention time of A=16.63 min
tB=retention time of B=17.63 min
WA=peak of A=1.11 min
WB=peak of B=1.21 min
The mathematical expression for the resolution is:
![Re_{s} =\frac{2(t_{B}-t_{A})}{W_{A}+W_{B} } =\frac{2*(17.63-16.63)}{1.11+1.21} =0.8621](https://tex.z-dn.net/?f=Re_%7Bs%7D%20%3D%5Cfrac%7B2%28t_%7BB%7D-t_%7BA%7D%29%7D%7BW_%7BA%7D%2BW_%7BB%7D%20%7D%20%3D%5Cfrac%7B2%2A%2817.63-16.63%29%7D%7B1.11%2B1.21%7D%20%3D0.8621)
The mathematical expression for the time to elute the two species is:
![\frac{t_{2}}{t_{1}} =(\frac{Re_{B} }{Re_{s} } )^{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bt_%7B2%7D%7D%7Bt_%7B1%7D%7D%20%3D%28%5Cfrac%7BRe_%7BB%7D%20%7D%7BRe_%7Bs%7D%20%7D%20%29%5E%7B2%7D)
Here
ReB = 1.5
![t_{2} =t_{1} *(\frac{Re_{B} }{Re_{s} } )^{2} =17.63*(\frac{1.5}{0.8621} )^{2} =53.3727min](https://tex.z-dn.net/?f=t_%7B2%7D%20%3Dt_%7B1%7D%20%2A%28%5Cfrac%7BRe_%7BB%7D%20%7D%7BRe_%7Bs%7D%20%7D%20%29%5E%7B2%7D%20%3D17.63%2A%28%5Cfrac%7B1.5%7D%7B0.8621%7D%20%29%5E%7B2%7D%20%3D53.3727min)