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4 years ago

12

Which of the following processes is similar to the problem-solving process?

1 answer:

alina1380 [7]4 years ago

6 0

Answer:

The engineering design process

Explanation:

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In a Rankine cycle, superheated steam that enters the turbine at 1273.15 K and 1.8 MPa is then expanded to a vapor at 0.1 MPa. W

GrogVix [38]

Answer:

The shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

Explanation:

Given:

Temperature $T = 1273.15$ K

Initial Pressure $P_{1} = 1.8$ MPa

Final pressure $P_{2} = 0.1$ MPa

From the table superheated,

$h_{i} = 4635$ $\frac{K J}{Kg}$ and $h_{f} = 2706.54$ $\frac{K J}{Kg}$

Work done by shaft is,

$W = h_{f} - h_{i}$

$W = 2706.54 - 4635$

$W = -1928.46 \frac{kJ}{kg}$

But here efficiency is 0.56,

So work generated per kg is,

Work = $0.56 \times(- 1928.46)$

Work = $-1.3$ $\frac{MJ}{kg}$

Therefore, the shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

6 0

3 years ago

6.8.1: Function pass by pointer: Transforming coordinates. Define a function CoordTransform() that transforms its first two inpu

Black_prince [1.1K]

Answer:

The code is in the Explanation

Explanation:

#include <iostream>

using namespace std;

int main() {

int xValNew = 0;

int yValNew = 0;

CoordTransform(3, 4, xValNew, yValNew);

cout << "(3, 4) becomes " << "(" << xValNew << ", " << yValNew << ")" << endl;

return 0;}

6 0

3 years ago

Water flows through a horizontal 60 mm diameter galvanized iron pipe at a rate of 0.02 m3/s. If the pressure drop is 135 kPa per

maksim [4K]

Answer:

pipe is old one with increased roughness

Explanation:

discharge is given as

$V =\frac{Q}{A} = \frac{ 0.02}{\pi \4 \times (60\times 10^{-3})^2}$

V = 7.07 m/s

from bernou;ii's theorem we have

$\frac{p_1}{\gamma} +\frac{V_1^2}{2g} + z_1 = \frac{p_2}{\gamma} +\frac{V_2^2}{2g} + z_2 + h_l$

as we know pipe is horizontal and with constant velocity so we have

$\frac{P_1}{\gamma } + \frac{P_2 {\gamma } + \frac{flv^2}{2gD}$

$P_1 -P_2 = \frac{flv^2}{2gD} \times \gamma$

$135 \times 10^3 = \frac{f \times 10\times 7.07^2}{2\times 9.81 \times 60 \times 10^{-5}} \times 1000 \times 9.81$

solving for friction factor f

f = 0.0324

fro galvanized iron pipe we have $\epsilon = 0.15 mm$

$\frac{\epsilon}{d} = \frac{0.15}{60} = 0.0025$

reynold number is

$Re =\frac{Vd}{\nu} = \frac{7.07 \times 60\times 10^{-3}}{1.12\times 10^{-6}}$

Re = 378750

from moody chart

$For Re = 378750 and \frac{\epsilon}{d} = 0.0025$

$f_{new} = 0.025$

therefore new friction factor is less than old friction factoer hence pipe is not new one

now for Re = 378750 and f = 0.0324

from moody chart

we have $\frac{\epsilon}{d} =0.006$

$\epsilon = 0.006 \times 60$

$\epsilon = 0.36 mm$

thus pipe is old one with increased roughness

5 0

3 years ago

2. In the above figure, what type of cylinder arrangement is shown in the figure above?

Oduvanchick [21]

Answer:

C. Horizontal

Explanation:

The type of cylinder arrangement that is shown in the figure is "Horizontal"

The arrangement is actually horizontal which is known to be horizontally opposed engine. Such engine is known as flat engine. It's a piston engine that has the cylinders located on either side of a crankshaft. It is usually located at the central crankshaft. This type of engine has performance advantage over others.

5 0

4 years ago

Consider a car manufacturing firm, with more than 100 facilities worldwide. What would be the positive aspects of having high nu

liberstina [14]

More work getting done and faster

7 0

3 years ago

Read 2 more answers