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Ugo [173]
3 years ago
6

Which is the magnitude of the vector 13 m/s to the east

Physics
2 answers:
Anika [276]3 years ago
7 0

Answer:

The correct answer is 13 m/s.

Aliun [14]3 years ago
6 0

I don’t know undertansdsje

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What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward
Yuri [45]

Answer:

q = 2.067 \times 10^{-5}\ C

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

q =\dfrac{mg}{E}

q =\dfrac{0.00141 \times 9.81}{670}

q = 2.067 \times 10^{-5}\ C

Charge of the particle is equal to q = 2.067 \times 10^{-5}\ C

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3 years ago
A human services professional has worked with a particular client for a couple of years. The client
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Answer:

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Explanation:

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Force is measured in units called
balu736 [363]

Answer:

Newtons

Explanation:

8 0
3 years ago
Read 2 more answers
What is the energy equivalent of an object with a mass of 1.83 kg?
xxMikexx [17]
To determine the energy equivalent of an object, we use the famous equation of Einstein which is E=mc^2 where m is the mass of the object and c is the speed of light (3x10^8 m/s). We calculate as follows:

E = mc^2
E = 1.83 kg (3x10^8 m/s)^2
E = 1.647x10^17 J
6 0
3 years ago
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Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 50 km/h. After six hours,
Xelga [282]
A )
t 1 = 2 h,  t 2 = 6 h
Δ t = t 2 - t 1 = 6 - 2 = 4 h
54 = 50 + a Δ t
54 = 50 + 4 a
4 a = 54 - 4
4 a = 4
a = 4 : 4
a = 1 km/h²
v o = 48 km/h
An equation that can be used to describe the velocity of the car at the different times is:
v = 48 + t
B ) The graph is in the attachment. 
Download docx
6 0
3 years ago
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