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bija089 [108]
3 years ago
5

What is a solvent? what is a solute ? which one is usually found in the greater amount?

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
5 0
A solvent is something that can have something else dissolved within it and turn into a homogenous solution, while the solute is that something else that can be dissolved into the solvent. Usually, the solvent is found in greater amount because most (except for rare cases) solvents have a saturation point that is below the equal-mass point.
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How do you determine the chemical reactivity for metals by using the periodic table?
vesna_86 [32]

Answer:

Chemical reactivity increases down a group and decreases from left to right of a period.

Explanation:

The higher the ionization energy is, the lower the reactivity is. Since the ionization energy is highest in the top right corner of the periodic table, we can assume that the most reactive elements are in the opposite bottom left corner. This is because the electrons that react are farther away from the nucleus thus experience less attraction to the nucleus (called nuclear shielding). Therefore their electrons are more easily removed than elements that don't ecperience nuclear shielding.

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In North America, where is population density the highest ?
zepelin [54]

Near the coasts and Great Lakes.

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The correct answer for the addition of 5.8 g + 2.26g + 1.311g + 2 g is?
jeka94

Answer:

= 11.371g

Explanation:

Hope This Helps! :]

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2 years ago
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qwelly [4]

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neutrons is metal.......

6 0
3 years ago
A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
2 years ago
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