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2 years ago

6. What is the equilibrium constant for the following reaction? C+02 = CO2

Chemistry

1 answer:

Orlov [11]2 years ago

8 0

<h3> $\tt Kc=\dfrac{[CO_2]}{[C][O_2]}$ </h3><h3>Further explanation</h3>

Given

Reaction

C+02 = CO2

Required

The equilibrium constant

Solution

The equilibrium constant is the ratio of concentration or pressure between the product and the reactant with each reaction coefficient raised

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

$\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}$

So for the reaction :

C+O₂ ⇔ CO₂

$\tt Kc=\dfrac{[CO_2]}{[C][O_2]}$

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Consider the chemical equation for the production of water: 2 H2+O2→2 H2O. If 100 grams of oxygen gas are used, what would the p

Cerrena [4.2K]

Answer:

The percentage yield of water is 66.67%.

Explanation:

$2H_2+O_2\rightarrow 2H_2O$

Mass of oxygen gas = 100 g

Moles of oxygen gas = $\frac{100 g}{32 g/mol}=3.125 mol$

According to reaction, 1 mole of oxygen gives 2 moles of water, then 3.125 moles of oxygen will give:

$\frac{2}{1}\times 3.125 mol=6.25 mol$

Mass of 6.25 moles of water :

6.25 mol × 18 g/mol = 112.5 g

Theoretical yield of water = 112.5 g

Experimental yield of water = 75 g

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2 years ago

How many oxygen atoms are there in 582 grams of caffeine (CH10N402, 194 g/mol)? Avogadro's Number: 1 mole = 6.02 x 1023 species

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Answer:

3.61 * 10 ²⁴atoms.

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = 582 g

m = 194 g/mol

The number of moles can be calculated from the above formula , and substituting the respective values ,

n = w / m = 582 g / 194 g/mol = 3 mol

In the molecular formula of caffeine ,

<u>In 1 mole of caffeine their are - 2 moles of Oxygen. </u>

Therefore , in 3 moles of Caffeine there will be 6 moles of oxygen.

As well know ,

one mole of any substance contains 6.023*10²³ atoms,

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Answer:

The balanced chemical equation will be " $NO_{2}+O\rightarrow NO+O_{2}$ ".

Explanation:

The given equation is:

$2NO_{2}\rightarrow 2NO+O_{2}$

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<u></u> $NO_{2}+O\rightarrow NO+O_{2}$ ...(equation 2)

On adding "equation 1" and "equation 2", we get

⇒ $NO_{2}+NO_{2}+O\rightarrow NO+O+NO+O_{2}$

⇒ $2NO_{2}\rightarrow 2NO+O_{2}$

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