<h3>
Answer:</h3>
46.67 m/s²
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of a rocket = 3 kg
- Force applied = 140 N
we are supposed to calculate the acceleration of the rocket;
- We are going to use the second Newton's law of motion;
- According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
- This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.
Therefore;
F = Ma
In this case;
Rearranging the formula
a = F ÷ m
= 140 N ÷ 3 kg
= 46.67 m/s²
Thus, the acceleration of the rocket is 46.67 m/s²
Given the answers I would say B, Is your best choice because when the light goes through a hole it spreads out, because most light rays (<) outward.
Distance from the reference point
Answer:
T= 8.061N*m
Explanation:
The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:
T = Fr
where F is the force, r the radius.
if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.
Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:
r = 
r = 0.5374m
Finally, replacing the value of r and F, we get that the maximun torque is:
T = 15N(0.5374m)
T= 8.061N*m
