All categories

3 years ago

What are 3 common sources of voltage difference?

1 answer:

3 0

We are asked to enumerate 3 different sources of potential difference and the answers are listed below:
1. There was two parallel sources and voltage of each source is different from each other.
2. Different batteries are connected.
3, Different values of resistors were used in the circuit.

You might be interested in

WILL UPVOTE!!!Physics help please!!

liubo4ka [24]

Speed v = initial speed u + acceleration a x time t
v=u+at = 2 + 4*3 = 14 m/s

8 0

3 years ago

g Calculate the maximum wavelength of light that will cause the photoelectric effect for potassium. Potassium has work function

Ivahew [28]

Answer:

λ = 5.4196 10⁻⁷m, λ = 541.96 nm this is green ligh

Explanation:

The photoelectric effect was explained by Eintein assuming that the light was made up of particles called photons and these collided with the electrons taking them out of the material.

K = h f -Ф

where K is the kinetic energy of the ejected electrons, hf is the energy of the light quanta and fi is the work function of the material.

The speed of light is related to wavelength and frequency

c = λ / f

f = c /λ

we substitute

K = h c / λ - Φ

for the case that they ask us the kinetic energy of the electons is zero (K = 0)

h c / λ = Ф

λ = h c / Ф

we calculate

λ = 6.63 10⁻³⁴ 3 10⁸ / 3.67 10⁻¹⁸

λ = 5.4196 10⁻⁷m

let's take nm

lam = 541.96 nm

this is green light

4 0

3 years ago

What is meaning of charge?

ludmilkaskok [199]

Answer:

demand (an amount) as a price for a service rendered or goods supplied.

Explanation:

to enter or record as an obligation against a person or his account. to accuse or impute a fault to (a person, etc), as formally in a court of law. to command; place a burden upon or assign responsibility toI was charged to take the message to headquarters.

3 0

2 years ago

Read 2 more answers

Positive Charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positiv

deff fn [24]

Answer:

electric field E = - k Q (1 /r(r-a)), force F = - k Q qo / r (r-a) and force for r>>a F ≈ - k Q qo / r²

Explanation:

You are asked to find the electric field of a continuous charge distribution, so we must use the equation

E = k ∫dp /r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C², r is the distance between the load distribution and the test charge, in this case everything is on the X axis.

We must find the charge differential (dq), let's use that uniformly distributed and create a linear charge density

λ = q / x

As it is constant, we can write it based on differentials

λ = dq / dx

dq = λ dx

We already have all the terms, let's integrate enter its limits, lower the distance from the left end of the distribution to the test charge (x = r) and the upper limit that is the distance from the left end of distribution to the test load ( x = r - a) where r> a

E = k ∫ λ dx / x²

E = k la (- 1 / x)

Let's get the negative sign from the parentheses

E = - k λ (1 / x)

E = - k λ (1 /(r-a) -1 /r) = - k λ [a / r (r-a)]

Let's change the charge density with the value of the total charge λ = Q / a

E = - k Q/a [a / r (r-a)]

E = - k Q (1 /r(r-a))

b) We calculate the force.

F = E qo

F = - k Q qo / r (r-a)

c) the force for charge porbe very far r >> a. In this case we can take r from the parentheses and neglect (a/r)