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Stolb23 [73]
3 years ago
5

What are 3 common sources of voltage difference?

Physics
1 answer:
rodikova [14]3 years ago
3 0
We are asked to enumerate 3 different sources of potential difference and the answers are listed below:
1. There was two parallel sources and voltage of each source is different from each other.
2. Different batteries are connected.
3, Different values of resistors were used in the circuit.

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what is the true answer in this question?Making a schedule on the things that need to be accomplished yes or no​
musickatia [10]

Answer:

yes

Explanation:

this is true don't believe other people whether right or wrong

5 0
2 years ago
(a) The stick is supported by a sharp point at the middle. On the left side, a weight of 100 g is suspended at 40 cm from the mi
Jet001 [13]

Answer:

20cm

Explanation:

Hello!

remember that the condition for a body to be at rest is that the sum of its moments and its forces be zero,

To solve this problem you must draw the free body diagram of the stick (attached image) and sum up moments at point 0 (where the sharp is located), which results in the following equation

(100g)(40cm)=x(200g)

X=\frac{(100)(40)}{(200)} =20cm

6 0
3 years ago
How does the table show that the balloon went downwards ?
o-na [289]

Answer:

I am going to guess it shows that the balloon is going downwards because the speed of rise is in the negatives for the last 2.

6 0
2 years ago
A sonar emits a sound signal of frequency 40000Hz, towards the bottom of the sea.
kap26 [50]

Answer:

0.000025s

Explanation:

Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s

8 0
2 years ago
For a body falling freely from rest​ (disregarding air​ resistance), the distance the body falls varies directly as the square o
jasenka [17]

Answer:

The answer to the question is

The object would fall 57.625 m in the first 5 seconds

Explanation:

To solve the question, we note that

the height of fall = 490 ft = ‪149.352‬ m

Time to touch the ground = 7 seconds

We are required to find out how far the object falls in the first 5 seconds

We apply the relation

S = u·t + 0.5×g·t ² = We then have

‪149.352‬ = U×7+0.5*9.81*49 From where u = -13 m/s

Therefore to find how far it falls in the first 5 seconds, we have

-13*5 + 0.5*9.81*25 = 57.625 m

5 0
2 years ago
Read 2 more answers
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