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3 years ago

What is the net force acting on a 2kg obgect that accelerates from rest at a rate of 5m/s/s/?

Physics

1 answer:

Alekssandra [29.7K]3 years ago

8 0

Explanation:

mass=2kg

acceleration=5m/s/s

Force=mass×acceleration

Force=2×5

Force=10N

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Please help ASAP....

Solnce55 [7]

Explanation:

its easy everone can do it .....let me know

5 0

3 years ago

Ishani and John now try a problem involving a charging capacitor. An uncharged capacitor with C = 6.81 μF and a resistor with R

DENIUS [597]

Answer:

$Q=81.72\times10^{-6}C$

$I=2.1\times10^{-5}A$

Explanation:

The maximum charge on the capacitor will be, at the end of the process, given by the formula (and for our values):

$Q=CV=(6.81\times10^{-6}F)(12V)=81.72\times10^{-6}C$

The maximum current on the resistor will be, at the beginning of the process, given by the formula (and for our values):

$I=\frac{V}{R}=\frac{12V}{5.8\times10^{5}\Omega}=2.1\times10^{-5}A$

5 0

3 years ago

The diagram shows what happens to a system undergoing an adiabatic process.

posledela

The answer is:
B. <span>X: Work is done to the system and temperature increases.
Y: Work is done by the system and temperature decreases.</span>

5 0

4 years ago

Read 2 more answers

Bowling balls are roughly the same size, but come in a variety of weights. Given its official radius of roughly 0.110 m, calcula

velikii [3]

Answer:

6.1328 kg

60.16284 N

Explanation:

r = Radius of ball = 0.11 m

$\rho$ = Density of fluid = $1.1\times 10^3\ kg/m^3$ (Assumed)

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of ball

V = Volume of ball = $\frac{4}{3}\pi r^3$

The weight of the bowling ball will balance the buouyant force

$W=F_b\\\Rightarrow mg=V\rho g\\\Rightarrow m=\frac{V\rho g}{g}\\\Rightarrow m=V\rho\\\Rightarrow m=\frac{4}{3}\pi 0.11^3\times 1.1\times 10^3\\\Rightarrow m=6.1328\ kg$

The mass of the bowling ball will be 6.1328 kg

Weight will be $6.1328\times 9.81=60.16284\ N$

5 0

3 years ago

Question 8

Viefleur [7K]

Answer:

96 Joules

Explanation:

The formula for work is Fnet times displacement (F x d = w) which, in this case, 48N is the Fnet and 2m as the displacement. Then all we need to do is multiply these two and we get 96 Joules.

3 0

3 years ago