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2 years ago

Is decay pool or flux

Chemistry

1 answer:

mash [69]2 years ago

7 0

Answer:

A single carbon pool can often have several fluxes both adding and removing carbon simultaneously. For example, the atmosphere has inflows from decomposition (CO2 released by the breakdown of organic matter), forest fires and fossil fuel combustion and outflows from plant growth and uptake by the oceans.

Explanation:

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A student plans to add HCL to a solution containing pb(NO3)2 (aq). To determine how much Pb2+ will precipitate from solution whe

WINSTONCH [101]

Answer:

Option C. Ksp for PbCl₂

Explanation:

The equilibrium constant that is established between a solid and its ions in a saturated solution is what is known as Ksp (solubility product). It is an equilibrium constant based on concentrations.

The concentrations must be equilibrium, that is, concentrations of the ions in a saturated solution. To be sure of such saturation it is convenient to form a precipitate.

The smaller the Kps, the more insoluble the salt

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3 years ago

2. In which state of matter do particles vibrate in place? *

Mariana [72]

solid.................

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3 years ago

Read 2 more answers

Suppose that some FeSCN2+ is added to the above solution to shift the equilibrium. When equilibrium is re-established, the follo

kiruha [24]

Explanation:

The given reaction equation will be as follows.

$[FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]$

Let is assume that at equilibrium the concentrations of given species are as follows.

$[Fe^{3+}] = 8.17 \times 10^{-3}$ M

$[SCN^{-}] = 8.60 \times 10^{-3}$ M

$[FeSCN^{2+}] = 6.25 \times 10^{-2}$ M

Now, first calculate the value of $K_{eq}$ as follows.

$K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}$

= $\frac{8.17 \times 10^{-3} \times 8.60 \times 10^{-3}}{6.25 \times 10^{-2}}$

= $11.24 \times 10^{-4}$

Now, according to the concentration values at the re-established equilibrium the value for $[FeSCN^{2+}]$ will be calculated as follows.

$K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}$

$11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}$

$[FeSCN^{2+}] = 5.66 \times 10^{-2}$ M

Thus, we can conclude that the concentration of $[FeSCN^{2+}]$ in the new equilibrium mixture is $5.66 \times 10^{-2}$ M.

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3 years ago

For the vaporization reaction Br2(l) → Br2(

oksian1 [2.3K]

The temperature at which the process be spontaneous is calculated as follows

delta G = delta H -T delta S

let delta G be =0

therefore delta H- T delta s =0

therefore T= delta H/ delta S
convert 31 Kj to J = 31 x1000= 31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K

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3 years ago

WILL MARK BRAINLY

DENIUS [597]

Answer:

its B i guess

Explanation:

7 0

2 years ago