Answer:
Wavelength of the photon depends on transition from different states.
Explanation:
The wavelength of the photon that is emitted from the atom during the transition depends on the transition from different states. If the photon is emitted from n=4 state to n=3 state, the wavelength of photon is 1875 while on the other hand, if the photon is emitted from n=5 state to n=3 state, the wavelength of photon is 1282. If the photon is emitted from n=3 state to n=2 state, the wavelength of photon is 656.
Answer:
3Na2SO4
Explanation:
3Na2SO4
# of molecules: 3 moles of Na2SO4 or 3 × 6.22 × 10^23 molecules.
# of elements: 3 elements l
Name of element: = Sodium, S = Sulphur, O = Oxygen
# of atoms: Na = 6 atoms, S= 3, O= 12
Total # of atoms: 21
The #3 is a Coefficient.
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3-Methylpentane is the IUPAC name for the substance.
whether in a continuous chain or a ring, the longest chain of carbons joined by a single bond serves as the basis for IUPAC nomenclature. According to a precise set of priorities, all deviations—whether they involve numerous bonds or atoms other than carbon and hydrogen—are denoted by prefixes or suffixes.
+3-Methylpentane is the IUPAC name for the substance in question. It has a lengthy chain of 5 carbon atoms, which gives it the prefix pent-, and a single bond is what gives it the postfix -ane (alkane). Given that the methyl group is present at the third carbon, it is 3-methylpentane.
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1.66 M is the concentration of the chemist's working solution.
<h3>What is molarity?</h3>
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
In this case, we have a solution of Zn(NO₃)₂.
The chemist wants to prepare a dilute solution of this reactant.
The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.
We want to know the concentration of this diluted solution.
As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:
= 
(1)
and we also know that:
n = M x 
If we replace this expression in (1) we have:
x 
= 
x
Where 1, would be the stock solution and 2, the solution we want to prepare.
So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is :
4.93 x 210 = 620 x
= 1.66 M
This is the concentration of the solution prepared.
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Answer:
The density of copper is 0.5 g/mL
Explanation:
Given data:
Mass of copper = 6 g
Volume of copper = 12 mL
Density of copper = ?
Solution:
Formula:
d = m/v
d = density
m = mass
v = volume
d = 6 g/ 12 mL
d = 0.5 g/mL
Thus, the density of copper is 0.5 g/mL
