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rewona [7]
2 years ago
8

Explauin this plazz if u explain this to me i wil give brainlist

Physics
1 answer:
KonstantinChe [14]2 years ago
8 0

The energy that would be released if the mass was converted to energy is 9 * 10^-4 J

<h3>What is Einstein equation?</h3>

According to the Einstein equation, mass and energy can be interconverted. This is possible by the use of the equation E = mc^2

Where;

m = mass

c = speed of light

Hence;

E = 1 * 10^-20 Kg * (3 * 10^8 m/s)^2

E = 9 * 10^-4 J

Learn more about Einstein equation:brainly.com/question/10809666

#SPJ1

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The answer is 0=45.2 degrees
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Which of the following are not examples of circular motion? Check all that<br> apply
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B.riding on a ferris wheel

E.a satellite orbiting the Earth

Explanation:

A person riding on a ferris wheel and a satellite orbiting the earth both depicts circular motion.

Circular motion is the motion of a body about a fixed axis or center.

  • The motion path of the body forms a circle around the center.
  • In circular motion, the travel path is along a circle.
  • An orbiting satellite traces out its orbit round the earth.
  • At certain times, it passes through that point over and over again.
  • This is similar to that of a ferris wheel

Other options gives other types of motion.

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3 years ago
To raise an armpit upward the muscle on one side of it contracts what happens Elton the muscle on the opposite side of the arm
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Answer:

It relaxes

Explanation:

I took the test I hope it helps

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3 years ago
What parts of an electric generator are connected?
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Answer:

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6 0
2 years ago
A small wooden block with mass 0.775 kg is suspended from the lower end of a light cord that is 1.50 m long. The block is initia
jeka94

Answer:

34.83 m/s

Explanation:

From the law of conservation of momentum,

initial momentum of bullet = final momentum of block + bullet

mv₀ = (m + M)V

V = mv₀/(m + M)

where m = mass of bullet = 0.0120 kg, v₀ = initial momentum of bullet, M = mass of block = 0.775 kg, V = final velocity of block + bullet.

Now, since the block + bullet rise a height of 0.725 m, from the law of conservation of energy,

potential energy change of block + bullet = kinetic energy change of block + bullet.

So (m + M)gh - 0 = -1/2(m + M)(V₁² - V²) where h = vertical height moved = 0.725 m and V₁ = velocity at 0.725 m and it has zero potential energy initially.

gh = -1/2(V₁² - V²)   (2)

Now, we obtain V₁ from

F = (m + M)V₁²/R since a centripetal force acts on the block + bullet at height 0.725 m. F = tension in chord = 4.88 N and R = length of cord = 1.50 m.

V₁ = √[FR/(m + M)]

Substituting V and V₁ into (2) above, we get

gh = -1/2(FR/(m + M) - [mv₀/(m + M)]²)

-2(m + M)²gh = FR(m + M) - (mv₀)²

v₀ = √([FR(m + M) + 2(m + M)²gh]/m)

substituting the values of the variables into v₀ we have

v₀ = √([4.88 N × 1.50 m × (0.0120 kg + 0.775 kg)  + 2(0.0120 kg + 0.775 kg)² × 9.8 m/s² × 0.725 m]/0.0120 kg)

= √([7.32 × 0.787 + 2(0.787)² × 9.8 m/s² × 0.725 m]/0.0120 kg)

= √(5.76 + 8.80)/0.012 kg

= √14.56/0.012

= √1213.40

= 34.83 m/s

So the initial speed v₀ = 34.83 m/s

7 0
3 years ago
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