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rewona [7]
2 years ago
8

Explauin this plazz if u explain this to me i wil give brainlist

Physics
1 answer:
KonstantinChe [14]2 years ago
8 0

The energy that would be released if the mass was converted to energy is 9 * 10^-4 J

<h3>What is Einstein equation?</h3>

According to the Einstein equation, mass and energy can be interconverted. This is possible by the use of the equation E = mc^2

Where;

m = mass

c = speed of light

Hence;

E = 1 * 10^-20 Kg * (3 * 10^8 m/s)^2

E = 9 * 10^-4 J

Learn more about Einstein equation:brainly.com/question/10809666

#SPJ1

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An object of mass 3 kg, moving with and sticks to an object of mass 2.00 kg with an initial velocity of 3.00 m/s. Find the final
Aleonysh [2.5K]

Answer:

1.8 m/s

Explanation:

momentum = mass × velocity

initial momentum = m1v1+m2v2

                             = 3×3 +2×0 = 9+0= 9 kg m/s

let combined velocity be V

HENCE  

final momentum = total mass × velocity

                            = (3+2) × V = 5V

According to law of conservation of momentum

final momentum = initial momentum

5V = 9

V =9/5

V = 1.8 m/s

8 0
3 years ago
How long does it take a microwave of power 0.2kW to sue 10000 J of energy
olasank [31]

Answer:

50s .

Explanation:

\frak{\pink{Given}}\begin{cases}\textsf{ The power of microvave is 0.2kW .}\\\textsf{ Amount of energy is 10000 J .}\end{cases}

Here the power of the microwave is 0.2kW . And as we know that ,

  • Rate of doing work is called power .

So from the definition , we have ;

\sf\longrightarrow Power =\dfrac{Work}{time}

  • Here the work done is equal to the energy consumed by the microwave i.e. 10000 J .So we can write it as ,

\sf\longrightarrow Power =\dfrac{Energy}{time}

\sf\longrightarrow 0.2kW = \dfrac{10^4 J }{t} \\

\sf\longrightarrow 0.2 * 1000 W =  \dfrac{10^4 J }{t}

Cross multiply ,

\sf\longrightarrow t = \dfrac{ 10^4 }{ 0.2 * 10^3}s=\dfrac{10^4}{2*10^2} s

Simplify ,

\sf\longrightarrow \boxed{\bf t = 50s}

<h3>Hence the time taken is 50s .</h3>
5 0
2 years ago
Suppose you are myopic (nearsighted). You can clearly focus on objects that are as far away as 52.5 cm away. You can clearly foc
Lilit [14]

Answer:

Explanation:

Image of distant object will be made at far point or at 52.5 so

object distance u = infinity

image distance v = - 52.5 cm

focal length required = f

Lens formula

1 / v - 1 / u = 1 / f

1 /  - 52.5 - 0 = 1 / f

f =  -52.5 cm

= -.525 m

Power P = 1 / f = -  1 / .525

= -  1.90

now , for eye with glass we shall find new near point .

v = ?

u = - 17.2 cm

f = -  52.5 cm

1 / v - 1 / u = 1 / f

  1 / v + 1 / 17.2 = -  1 / 52.5

1 / v  = - 1 / 17.2 -    1 / 52.5

= - .05813 -  .019

= - .07713

u = - 12.96 cm

so new near point will be 12.96 cm

5 0
3 years ago
Mr.G I running down the street trying to catch the bus. He is one city block away (200m) and this bus is leaving in 10s.
Sauron [17]

Answer:

a) 20 m/s

b) No

Explanation:

a)

Mr. G needs to run x= 200 m in t = 10 seconds to catch the bus.

Knowing the speed is computed as

\displaystyle v=\frac{x}{t}

We have

\displaystyle v=\frac{200m}{10s}=20m/s

b)

The fastest human can run 12 m/s, so Mr. G won't be able to catch the bus because he needs to run faster than that

6 0
4 years ago
A piece of taffy slams into and sticks to an identical piece of taffy at rest. The momentum of the combined pieces after the col
Marina CMI [18]

Answer:

D) 50%

Explanation:

According to conservation of momentum:

m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}

Assuming that the second taffy started at rest, both pieces have the same mass and that they combined after the collision, their final velocity is:

m v_{1i} = (m+m) v_{f}\\v_{f} = 0.5 v_{1i}

The initial kinetic energy of the system is:

E_{ki} = \frac{m*v_{1i}^2}{2}

Since the second taffy was not moving, it had no kinetic energy at first.

The initial kinetic energy of the system is:

E_{kf} = \frac{2m*v_{f}^2}{2}\\E_{kf} = \frac{2m*(0.5v_{1i})^2}{2}\\E_{kf} = \frac{0.5m*v_{1i}^2}{2}

The percentage of kinetic energy that becomes heat is given by:

H=1 - \frac{E_{kf}}{E_{ki}}\\H=1 - \frac{\frac{0.5m*v_{1i}^2}{2}}{\frac{m*v_{1i}^2}{2}}\\\\H=1- 0.5 = 0.5

THerefore, 50% of the kinetic energy becomes heat

8 0
3 years ago
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