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rewona [7]
2 years ago
8

Explauin this plazz if u explain this to me i wil give brainlist

Physics
1 answer:
KonstantinChe [14]2 years ago
8 0

The energy that would be released if the mass was converted to energy is 9 * 10^-4 J

<h3>What is Einstein equation?</h3>

According to the Einstein equation, mass and energy can be interconverted. This is possible by the use of the equation E = mc^2

Where;

m = mass

c = speed of light

Hence;

E = 1 * 10^-20 Kg * (3 * 10^8 m/s)^2

E = 9 * 10^-4 J

Learn more about Einstein equation:brainly.com/question/10809666

#SPJ1

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While in sketch mode, the number displayed to the right of the cursor defines the sketch element`s exact size. Therefore, there
galina1969 [7]

Answer:

B) False.

Explanation:

Most of the times, the numbers that appears right to the cursor are representing the coordinates (x & y) of the cursor. So as the cursor moves around the screen those number changes accordingly.Therefore its wrong to say that there is no need to add a dimension to set the dimensional value.

7 0
2 years ago
A kite is 100m above the ground. if there are 200m of string out what is the angle between the string and the horizontal? (assum
jeka57 [31]

Answer :  The angle between the string and the horizontal is 30 degrees

Explanation:  Imagine this a a triangle where the length of the string (200m) is the hypotenuse and the height of the kite is the opposite side (100m) .

Let the angle between the string and the horizontal be theta.

Now  sin (Theta) = opposite side/hypotenuse

                             =  100/200 = 1/2

Therefore Theta = Sin ⁻¹ ( 1/2 )

Theta = 30 degrees

4 0
3 years ago
A runner exerts a net force of 335 n to accelerate at a rate of 2.5 m/s what is the runners mass
Olegator [25]
F=ma
M=F/a
M=335/2.5
M=134 kg
8 0
3 years ago
If you were to walk at a constant speed 20m/s for 30 seconds, how far would you walk?
lana [24]

Answer:

600m

Explanation:

30×20 at a constant speed is 600m.

6 0
3 years ago
A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
2 years ago
Read 2 more answers
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