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ss7ja [257]
3 years ago
9

How would you find force of the ping pong ball rolling down the track?

Physics
1 answer:
Alina [70]3 years ago
6 0
<h3>Force of the ping pong ball rolling down the track:</h3><h3 /><h2>Answer</h2><h3>Weight </h3>

               a) weight's vertical component = Normal upward force

               b) weight's horizontal component = Friction force = (mass of ball)(acceleration)

These forces depend upon the track,

1) inclined or horizontal

2) steepness.

<h2>Explanation</h2>

The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the weight which points along the direction of the ball's motion can accelerate the ball.

<em>weight's horizontal component = Friction force = (mass of ball)(acceleration)</em>

The other component pushes the ball into the ramp, and the ramp pushes back.

If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp.

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A spherically-spreading EM wave comes from a 104.0 W source. At a distance of 9.6 m, what is the intensity of the wave?
Nookie1986 [14]

Answer:

Approximately 0.0898 W/m².

Explanation:

The intensity of light measures the power that the light delivers per unit area.

The source in this question delivers a constant power of \rm 104.0\; W. If the source here is a point source, that \rm 104.0\; W of power will be spread out evenly over a spherical surface that is centered at the point source. In this case, the radius of the surface will be 9.6 meters.

The surface area of a sphere of radius r is equal to 4\pi r^{2}. For the imaginary 9.6-meter sphere here, the surface area will be:

\rm 4\pi \times (9.6\; m)^{2} \approx 1158.12\; m^{2}.

That \rm 104.0\; W power is spread out evenly over this 9.6-meter sphere. The power delivered per unit area will be:

\displaystyle\rm  \frac{104.0\; W}{1158.12\; m^{2}}\approx 0.0898\; W\cdot m^{-2}.

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3 years ago
What is the velocity of the 100 kg cart at point b?
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I believe the answer is c
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When a net force of 17.0 newtons is applied to a dictionary placed on a frictionless table, it accelerates by 3.75 meters/second
4vir4ik [10]
Force = (mass) x (acceleration)    (Newton's second law of motion)

Divide both sides of the equation by 'acceleration', and you have

Mass = (force) / (acceleration)

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Which of the following is the best example of uniform circular motion? A. A child riding on a constantly spinning merry-go-round
Ulleksa [173]

A. because as the merry-go-round spins the child accelerates towards the center of the merry-go-round at a uniform rate.

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