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Sergeeva-Olga [200]
2 years ago
5

How do you breed a linner?

Engineering
2 answers:
sladkih [1.3K]2 years ago
8 0

Answer:

linner ​Definitions and Synonyms

​noun. DEFINITIONS1. 1. a meal eaten between lunch and dinner. “Linner” or “dunch” is served between 3-5 p.m., often a time for restaurants to close and prepare for dinner rush

Explanation:

you can't breed a (linner)

Marrrta [24]2 years ago
6 0

Answer:  e- Just- e-

Explanation:

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Mandarinka [93]

Answer:

I found the word!

It was Free points.

5 0
3 years ago
Read 2 more answers
1. Copy the file Pay.java (see Code Listing 1.1) from the Student CD or as directed by your instructor. 2. Open the file in your
Mrac [35]

Answer:

Code Listing 1.1 (Pay.java)

import java.util.Scanner; // Needed for the Scanner class

/**

This program calculates the user's gross pay.

*/

public class Pay

{

public static void main(String[] args)

{

// Create a Scanner object to read from the keyboard. Scanner keyboard = new Scanner(System.in);

// Identifier declarations

double hours; // Number of hours worked

double rate; // Hourly pay rate double pay; // Gross pay

// Display prompts and get input. System.out.print("How many hours did you work? "); hours = keyboard.nextDouble();

System.out.print("How much are you paid per hour? ");

rate = keyboard.nextDouble();

// Perform the calculations. if(hours <= 40)

pay = hours * rate;

else

pay = (hours - 40) * (1.5 * rate) + 40 * rate;

// Display results. System.out.println("You earned $" + pay);

}

}

Code Listing 1.2 (SalesTax.java)

import java.util.Scanner; // Needed for the Scanner class

/**

This program calculates the total price which includes

sales tax.

*/

public class SalesTax

{

public static void main(String[] args)

{

// Identifier declarations final double TAX_RATE = 0.055; double price;

double tax

double total; String item;

// Create a Scanner object to read from the keyboard. Scanner keyboard = new Scanner(System.in);

// Display prompts and get input. System.out.print("Item description: "); item = keyboard.nextLine(); System.out.print("Item price: $");

price = keyboard.nextDouble();

// Perform the calculations. tax = price + TAX_RATE;

totl = price * tax;

// Display the results. System.out.print(item + "  $"); System.out.println(price); System.out.print("Tax $"); System.out.println(tax); System.out.print("Total $"); System.out.println(total);

}

}

5 0
3 years ago
A crystalline grain of aluminum in a metal plate is situated so that a tensile load is oriented along the [1 1 1] direction. Wha
Ivenika [448]

Answer: required tensile stress is 0.889 MPa

Explanation:

Given that;

tensile load is oriented along the [1 1 1] direction

shear stress is 0.242 MPa along [1 0 1] in the (1 1 -1) plane

first we determine

λ which is Angle between  [1 1 1]  and  [1 0 1]

so

cosλ = [ 1(1) +  1(0) + 1(1) ] / [ √(1² + 1² + 1²) √(1² + 0² + 1²)]

= 2 / √3√2 =  2/√6

Next, we determine ∅ which is angle between [1 1 1]  and  [1 1 -1]

so,

cos∅ = [ 1(1) +  1(1) + 1(-1) ] / [ √(1² + 1² + 1²) √(1² + 1² + (-1)²)]

cos∅ = [ 2-1] / [√3√3 ]

cos∅ = 1/3

Now, we know that;

σ = T_stress/cosλcosθ

so we substitute

σ = 0.242 / ( 2/√6 × 1/3 )

σ = 0.242 / 0.2721

σ = 0.889 MPa

Therefore, required tensile stress is 0.889 MPa

3 0
3 years ago
A 150-lbm astronaut took his bathroom scale (a spring scale) and a beam scale (compares masses) to the moon where the local grav
kozerog [31]

Answer:

a)Wt =25.68 lbf

b)Wt = 150 lbf

F= 899.59 N

Explanation:

Given that

g = 5.48 ft/s^2.

m= 150 lbm

a)

Weight on the spring scale(Wt) = m g

We know that

1\ lbf=32.17 \ lmb.ft/s^2

Wt = 150 x 5.48/32 lbf

Wt =25.68 lbf

b)

On the beam scale

This is scale which does not affects by gravitational acceleration.So the wight on the beam scale will be 150 lbf.

Wt = 150 lbf

If the plane is moving upward with acceleration 6 g's then the for F

F = m a

We know that

1\ ft/s^2= 0.304\ m/s^2

5.48\ ft/s^2= 1.66\ m/s^2

a=6 g's

a=9.99\ m/s^2

So

F = 90 x 9.99 N

F= 899.59 N

3 0
3 years ago
Water flows with a velocity of 3 m/s in a rectangular channel 3 m wide at a depth of 3 m. What is the change in depth and in wat
strojnjashka [21]

Answer: new depth will be 3.462m and the water elevation will be 0.462m.

The maximum contraction will be achieved in width 0<w<3

Explanation:detailed calculation and explanation is shown in the image below

8 0
3 years ago
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