By using the coefficient of linear expansion, the increase in the length of the metal plate is by 0.015m and in the area is by 0.3074
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The rate of change in length of a metal per degree change in temperature is known as the coefficient of linear expansion.
Given:
Coefficient of linear expansion, α = 29 x 
/k
Length, L1 = 10m
T1 = 25℃
T2 = 78℃
ΔT = 78 – 25 = 53℃
To find:
Change in length (ΔL) and area (ΔA) of metal plate = ?
Formula:
ΔL = α L1 ΔT
ΔA = A1 2 α ΔT
Calculations:
ΔL = 29 x x 10 x 53
ΔL = 0.01537m
ΔA = 100 x 2 x 29 x x 53
ΔA = 0.3074
A2 = 100.3074
Result:
The increase in the length and area is by 0.015m and 0.3074 respectively.
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Assuming that the gravitational field strength is 10 N/kg, the sum would look like this:
PEg=mgh
=60×10×10
=6000J
However, you will need to check that you are not meant to be using 9.8 N/kg as the gravitational field strength.
Answer:
a.) the speed at the bottom is greater for the steeperhill
Explanation:
since the energy at the bottom of the steeper hilis greater
As we can see from above that v is higher when h ishigher.
750 divide 50 which is 15n
or it is 750 times 50 which is 37500n
Answer:
Explanation:
For pendulum A: Length = L and gravity = g
The frequency of pendulum A is given by
Here, f is the frequency, L be the length
... (1)
For pendulum B: Length = 2L, gravity = g
The frequency of pendulum B is given by
.... (2)
Divide equation (1) by (2)
