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castortr0y [4]
2 years ago
7

In an inverse relationship, when one variable increases, the other___

Physics
1 answer:
eimsori [14]2 years ago
4 0

Answer:

In an inverse relationship, when one variable increases, the other variable decreases.

Explanation:

Hope this helps! ^^

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Kipish [7]

Answer:

Cd(NO3)2 + Na2S --> CdS + 2 NaNO3

Explanation:

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2 years ago
A(n) signal carries information by copying an original sound.
viva [34]
An analog signal carries information by copying an original sound
When we speak through the microphone, it turns our sound into some sort of electronic wave.
This electronic wave is caught by a recording device and later could be replicated into Mp3 file that we usually listen to
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2 years ago
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Identify three main ideas about models
soldi70 [24.7K]

Answer:

Approaches mathematical learning through inquiry

-Explore real contexts, problems, situations, and models

-Learning through doing shifts the focus on the students

-Problems have multiple entry and exit points

-Links to other disciplines

Explanation:

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6 0
3 years ago
Two objects experienced the same displacement in the same amount of time. The two objects must have the same -
nikdorinn [45]

If two object experiences the same displacement at the same time, the two objects must have the same average velocity.

The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

avg. \ velocity = \frac{\Delta \ displacement }{\Delta \ time} \\\\V = \frac{\Delta \ x}{\Delta t}

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

\frac{\Delta x_1}{\Delta t_1} = \frac{\Delta x_2}{\Delta t_2} = V_{avg}

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.

Learn more here: brainly.com/question/23856383

6 0
2 years ago
If the atmospheric pressure in a tank is 23 atmospheres at an altitude of 1,000 feet, the air temperature in the tank is 700F, a
liraira [26]

Answer:

W = 289.70 kg

Explanation:

Given data:

Pressure in tank = 23 atm

Altitude 1000 ft

Air temperature  in tank T = 700 F

Volume of tank = 800 ft^3 = 22.654 m^3

from ideal gas equation we have

PV =n RT

Therefore number of mole inside the tank is

\frac{1}{n} = \frac{RT}{PV}

              = \frac{8.206\times 10^{-5}} 644.261}{23\times 22.654}

               = 1.02\times 10^{-4}

               n = 10^4 mole

we know that 1 mole of air weight is 28.97 g

therefore, tank air weight is W = 10^4\times 28.91 g = 289700 g

               W = 289.70 kg

6 0
2 years ago
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