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1 year ago

A 4.28 m deep well acts as a closed pipe. When wind blows across the top, what is the third harmonic (f3) that it creates?

Physics

1 answer:

Ksenya-84 [330]1 year ago

4 0

The third harmonic frequency from the wave speed is 60.1 Hz.

<h3>What is wavelength?</h3>

Wavelength is the distance between identical points in the adjacent cycles of a waveform signal propagated in space or along a wire.

Let's first find the wavelength of the wave.

The length wavelength relationship

$\lambda = \frac{4}{3} L = \frac{4}{3} . 4.28m = 5.706m$

Now , we will find the third harmonic frequency from the wave speed formula:

$v = f\lambda \\\\f = \frac{v}{\lambda} \\\\f = \frac{343\frac{m}{8} }{5.706m} \\\\f = 60.1 Hz$

Therefore , the third harmonic (f3) is 60.1 Hz

Learn more about harmonic frequency:

brainly.com/question/12320829

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<h2><u>Background Information</u></h2>

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3 years ago

Read 2 more answers

A baseball has a momentum of 6.0 kg.m/s south and mass of 0.15kg. What’s the baseballs velocity?

Mashcka [7]

Answer:

<em>v=40 m/s south</em>

Explanation:

<u>Momentum </u>

It's a physical magnitude that measures the product of the mass by the velocity of a particle. Its units in the International System is kg.m/s and the formula is

$p=m.v$

Where m is the mass and v the velocity of the particle. If we wanted to solve for v, we have

$\displaystyle v=\frac{p}{m}$

The baseball has a momentum of 6.0 kg.m/s south and mass of 0.15kg, thus

$\displaystyle v=\frac{6}{0.15}=40\ m/s$

The velocity is directed to the south

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3 years ago

Radar is used to determine distances to various objects by measuring the round-trip time for an echo from the object. (a) How fa

zloy xaker [14]

Answer:

150000000000 m

0.0000005 seconds

33.33 ns

Explanation:

Speed of electromagnetic waves through vacuum = $3\times 10^8\ m/s$

Echo time = 1000 seconds

Echo time is the time taken to reach the object and come back to the observer

Distance = Speed×Time

$Distance=3\times 10^8\times \frac{1000}{2}=150000000000\ m$

Venus is 150000000000 m away from Earth

Time = Distance / Speed

$Time=\frac{75}{3\times 10^8}=0.00000025\ seconds$

Echo time will be twice the time

$Echo\ time=2\times 0.00000025=0.0000005\ seconds$

The echo time will be 0.0000005 seconds

Difference in time = Difference in distance / Speed

$\Delta t=\frac{\Delta d}{v}\\\Rightarrow \Delta t=\frac{10}{3\times 10^8}\\\Rightarrow \Delta=33.33\ ns$

The accuracy by which I will be able to measure the echo time is 33.33 ns

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3 years ago

How much metabolic energy is required for a 68kg person to run at a speed of 15km/hr for 15min ?

irga5000 [103]

<span>What I have here is exactly the same problem, however, with the time changed to 19 mins:

metabolic energy = metabolic power*time = 1.150*19*60 = 1.311 kJ..corresponding to 1.311/4.186 = 313,2 Cal or kcal

If we reasonably assume a metabolic eff.cy of 20%, it means we need to assume food for 1500 Cal approx.

Just plug the value t=15min to the equation and you will surely get the correct answer.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>

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3 years ago

Which quantity can be calculated using Newton’s second law of motion?

DiKsa [7]

Newton's 2nd law of motion:

Net Force = (mass) x (acceleration) .

The law shows the relationship among an object's mass
and acceleration, and the net force acting on it.

If you know any two of the quantities in the formula,
the law can be used to calculate the third one.

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3 years ago