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LiRa [457]
2 years ago
9

Discribe a test to distinguish between consentrated HNO3and H2SO4​

Chemistry
1 answer:
ollegr [7]2 years ago
8 0

Answer:

https://www.quora.com/What-is-the-difference-between-HNO3-and-H2SO4

Explanation:

HNO3 is a protic acid and H2SO4 is a diprotic acid, this means that while HNO3 donates a single H+ H2SO4 donates 2 H+ ions.

HNO3 is highly volatile as compared to H2SO4.

The components are different, the molecular weights and melting point and boiling points are different.

H2SO4 is dubbed the king of acids because it has a variety of reactions, while HNO3 has quite a few reactions it is not comparable to H2SO4’s

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Calculate the volume occupied by 0.845 mole of nitrogen gas, the pressure, and the temperature. Find the volume.
NeTakaya

Answer:

V = 15.9512 dm³

Explanation:

Given data:

Pressure = P = 1.37 atm

Temperature = T= 315 K

Number of moles of nitrogen= n = 0.845 mol

Volume = V = ?

Formula:

PV = nRT

Now we will put the values in equation.

V = nRT/ P

V = ( 0.845 mol× 0.0821 dm³.atm.K⁻¹.mol⁻¹ × 315 K) / 1.37 atm

V = 21.853 dm³. atm/  1.37 atm

V = 15.9512 dm³

5 0
4 years ago
Read 2 more answers
What is the order of discovery of the three subatomic particles
masya89 [10]

Protons, neutrons, and electrons are the three main subatomic particles found in an atom. Protons have a positive (+) charge. An easy way to remember this is to remember that both proton and positive start with the letter "P." Neutrons have no electrical charge.

thats what i found for you!

3 0
3 years ago
Ch4(g) + h2o(g) 3h2(g) + co(g) enthalpy of formation of CH4
Aneli [31]

Answer:

Kc=[[CO][H2]3[CH4][H2O]

3.90=(0.30)(0.10)3[CH4]×0.02

[CH4]=0.023.90×0.30×(0.10)3=5.85×10−2 M

Thus, the concentration of methane in the mixture is 5.85×10−2 M.

4 0
3 years ago
Measurements show that unknown compound has the following composition: element mass 62.1 % carbon, 10.5 % hydrogen and 27.6 % ox
barxatty [35]

Answer:

C3H6O

Explanation:

The percentage composition of the elements in the compound are given as follows:

62.1 % carbon = 62.1g of C

10.5 % hydrogen = 10.5g of H

27.6 % oxygen = 27.6g of O

Next, we convert each mass to mole by dividing by their molar/atomic mass

C = 62.1/12 = 5.175mol

H = 10.5/1 = 10.5mol

O = 27.6/16 = 1.725mol

Next, we divide each mole value by the smallest mole value (1.725)

C = 5.175mol ÷ 1.725 = 3

H = 10.5mol ÷ 1.725 = 6.086

O = 1.725mol ÷ 1.725 = 1

The empirical ratio approximately of C:H:O is 3:6:1, hence, the empirical formula is C3H6O

8 0
3 years ago
Which of the following is an example of pseudoscience?
Westkost [7]
Psychic experiences it the answer out of the 4 


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4 years ago
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