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Reil [10]
2 years ago
12

What is the name of this molecule?

Chemistry
1 answer:
Fiesta28 [93]2 years ago
7 0
Butanoic acid (Butyric acid)
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Which of the following statements about material bonding is correct? C O a. Ionic bonds are formed by the sharing of valence ele
Zina [86]

Answer: Option (b) is the correct answer.

Explanation:

In material bonding, there occurs Vander waal foces between the molecules in which their is either an induced or permanent dipole moment that attract molecules towards each other.

And, due to these forces the molecules are held together.

On the other hand, in a ionic bond there will always be transfer of electrons from one atom to another. This is because on atom which loses its valence electrons acquires a positive charge and another atom which gains the electrons acquires a negative charge.

Hence, these opposite charges strongly gets attracted towards each other forming a strong bond.

Whereas in a covalent bond, there will be sharing of electrons between the combining atoms.

In a metallic bond, there occurs a sea of electrons which is uniformly distributed throughout the solid substance or material.

Thus, we can conclude that the statement, Van der Waals bonds are formed by Van der Waals forces in which molecules or atoms have either an induced or permanent dipole moment to attract each other, about material bonding is correct.

5 0
3 years ago
Select the correct answer from each drop-down menu. An atom has 9 electrons and 9 protons at the start. If it loses 2 electrons,
aalyn [17]

Answer:

If it loses to electrons the net charge will be +2. If the atom instead gains 4 electrons, the net charge will be -4.

Explanation: When an atom loses electrons( which are negatively charged), it turns into a cation. This means since there is more protons(which are positively charged) than electrons, the charge is positive. The charge is positive and than the number of electrons lost. It is the exact opposite for gaining electrons.

3 0
2 years ago
Forensic toxicology involves not only the area of toxicology, but also the use of areas such as analytic chemistry and pharmacol
grandymaker [24]

Answer:

The answer is True

Explanation:

Forensic toxicology involves or  employs or uses disciplines such as analytical chemistry, pharmacology and clinical chemistry to aid medical or legal investigation.

3 0
3 years ago
Read 2 more answers
Which is the best analogy of a wave?
o-na [289]
T h e a s w e r i s d
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3 years ago
The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
3 years ago
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