Which element is the primary fuel used to generate electricity using nuclear energy?

Jasmine makes a note card about series circuits. she records the points shown. a 2 column table with 1 row. the column on the le

Bess [88]

Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.

<h3>What is a parallel circuit?</h3>

A parallel circuit is a circuit in which the components are connected to a common junction. This implies that if one bulb goes out in a parallel connection, all the bulbs will go out.

As such, Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.

Learn more about parallel connection: brainly.com/question/12400458

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7 0

2 years ago

Two equipotential surfaces surround a +1.70 x 10-8-C point charge. How far is the 120-V surface from the 54.0-V surface?

UNO [17]

Answer:

1.55 m

Explanation:

The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

$V =\frac{k*q}{r}$

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.

Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:

$r1 =\frac{k*q}{V1} = \frac{9e9 N*m2/C2*1.7e-8C}{120 V} = 1.28 m$

$r2 =\frac{k*q}{V2} = \frac{9e9 N*m2/C2*1.7e-8C}{54V} = 2.83 m$

The distance between both points, is just the difference between the radius of both spheres, as follows:

r₂ - r₁ = 1.55 m

5 0

3 years ago

The sun is 60° above the horizon. Rays from the sun strike the still surface of a pond and cast a shadow of a stick that is stuc

Kipish [7]

Answer:

shadow length 7.67 cm

Explanation:

given data:

refractive index of water is 1.33

by snell's law we have

$n_{air} sin30 =n_{water} sin\theta$

$1*0.5 = 1.33*sin\theta$

solving for $\theta$

$sin\theta = \frac{3}{8}$

$\theta = sin^{-1}\frac{3}{8}$

$\theta = 22 degree$

from shadow- stick traingle

$tan(90-\theta) = cot\theta = \frac{h}{s}$

$s = \frac{h}{cot\theta} = h tan\theta$

s = 19tan22 = 7.67 cm

s = shadow length

5 0

3 years ago

What is the weight of an object on Earth with a mass of 90.0kg?

Ksivusya [100]

Answer:

Weight (Force) = mass x acceleration due to gravity Weight = 90.0 kg x 9.80 m/s2 Weight = 882 N or 882 kg m/s2 Page 2 Newton's Notes 2 Gravity has an effect on an object in the vertical direction only.

8 0

3 years ago

Read 2 more answers

a car traveling at 24 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds what is its acceleration?

Irina18 [472]

We can solve for the acceleration by using a kinematic equation. First we should identify what we know so we can choose the correct equation.

We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.

The following equation has everything we need:

$v_f=v_i + at$

So plug in the known values and solve for a:

0 = 24 + 6a

-24 = 6a

a = -4 m/s^2

8 0

4 years ago