Which element is the primary fuel used to generate electricity using nuclear energy?

A 16.0 cm × 16.0 cm square loop of wire lies in the xy-plane with its bottom edge on the x-axis. The resistance of the loop is 0

Alina [70]

Answer:

the induced current is $I = 3.2768*10^{-4} \ \ A$

Explanation:

Given that :

side of the square (l) = 16 cm = 0.16 m

Magnetic field B = 0.750 y² t

Resistance R = 0.500 Ω

Time t = 0.490 s

Let consider a small rectangular; whose length is $l$ and breath is $dy$

Hence; to determine the magnetic flux through it small rectangular; we have:

$d \phi = B.dA \\ \\ d \phi = B (i * dy) \\ \\ d \phi = (0.750 \ y^2 t ) *(l *dy) \\ \\ d \phi = ( 0.75*t*l) y^2 dy \\ \\ d\phi = (0.75 tl) y^2 dy$

Let calculate the total flux in the square loop

$\phi = \int\limits^{y=l}_{y=0} B.dA \\ \\ \phi = \int\limits^{y=l}_{y=0} (0.75 \ t \ l ) y^2dy \\ \\ \phi = (0.75 \ t \ l )\frac{l^3}{3} \\ \\ \phi = (0.75 \ t )\frac{l^4}{3}$

Thus the total flux in the square loop is $\phi = (0.75 \ t )\frac{l^4}{3}$

Now; going to the induced emf; let consider the Faraday's Law

$V = \frac{d \phi}{dt}$

$V = \frac{d }{dt}(\frac{0.75*l^4}{3})*t$

$V = (\frac{0.75*0.16^4}{3})$

$V = 1.6384*10^{-4} \ V$

Finally ; the induced current I is given by the expression;

$I = \frac{V}{R} \\ \\ I = (\frac{1.6384*10^{-4}}{0.5})$

$I = 3.2768*10^{-4} \ \ A$

Therefore; the induced current is $I = 3.2768*10^{-4} \ \ A$

5 0

3 years ago

Why do the four outer planets have lower density than the four inner planets?

Marrrta [24]

Because the four outer planets are comprised of mostly gases give me a thanks or brainiest answer if this helps!

4 0

4 years ago

When you drop a pebble from height h, it reaches the ground with kinetic energy k if there is no air resistance. from what heigh

Komok [63]

-- The kinetic energy it has when it hits the ground is exactly
the potential energy it had just before you dropped it.

-- So if you want it to have twice as much kinetic energy at the bottom,
you want it to have twice as much potential energy at the top.

-- Potential energy = (mass)·(gravity)·(height).
The only one of those things that you can change is the height.

Looking at that equation, you can see that if you change the height,
the potential energy changes by the same factor.

So if you want the pebble to have twice as much potential energy,
you have to drop it from twice the original height. (2h)

4 0

3 years ago

A girl is sitting in a sled sliding horizontally along some snow (there is friction present).

Over [174]

Answer:

159 N

Explanation:

The force of friction, Fr is a product of coefficient of feiction and the normal force. Therefore, Fr=uN where N is the normal force and u is coefficient of friction. Here, we have two coefficients of friction but since it is sliding, then we use coefficient of kinetic energy. Substituting 0.25 for u and 636 N for N then

Fr=0.25*636=159 N

Therefore, the force of friction is equivalent to 159 N

4 0

3 years ago

A 7.5 nC point charge and a - 2.9 nC point charge are 3.2 cm apart. What is the electric field strength at the midpoint between

Oduvanchick [21]

Answer:

Net electric field, $E_{net}=91406.24\ N/C$