2 years ago

Science fair project

Physics

2 answers:

victus00 [196]2 years ago

8 0

For Science fair project you can do convection current

Explanation:

Show how to do the process

and then make a model to demonstrate

Materials required:

Potassium Permanganate,beaker,bunsen burner,water and retort stand

kondaur [170]2 years ago

5 0

Answer:

Explanation:

You can make a projector using convex lens and a mobile phone back of it

For more details search in you. tubeyou will get videos based on this

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A bullet is fired in a horizontal direction with a muzzle velocity of 300m/s.In the absence of air resistance,how far will it ha

Kruka [31]

Answer:

304.9m

Explanation:

Given

Velocity = 300m/s

Tim = 1sec

Required

Horizontal distance S

Using the formula

S= ut+1/2gt²

S = 300(1)+1/2(9.8)(1)²

S = 300+4.9

S = 304.9m

Hence the distance travelled is 304.9m

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2 years ago

D. A bargain hunter purchases a "gold" crown at a flea market. After she gets home, she hangs it from a scale and finds its weig

s2008m [1.1K]

Answer:

Wc = 7.84 weight of crown

Ww = 7.84 - 6.86 = .98 weight of water displaced

Density = 7.84 / .98 = 8 crown is 8 X that of water

Since gold has a density of 19.3 that of water the crown is certainly not 100 percent (if any) gold

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1 year ago

Two protons are 1 × 10−10 m apart (about one atomic radius). Which interaction between two protons is stronger, the gravitationa

anastassius [24]

Answer: The electric repulsion between the two protons is stronger than the gravitational attraction.

Explanation: Please see the attachments below

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3 years ago

When jogging outside you accidently bump into a curb. Your feet stop but your body continues to move forward and you end up on t

oee [108]

Inertia I think because I've heard it around school and in science

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2 years ago

A uniform electric field has a magnitude 1.80 kV/m and points in the +x direction. (a) What is the electric potential difference

EastWind [94]

Answer:

a)ΔV = 6.48 KV

b)ΔU =18.79 mJ

Explanation:

Given that

E= 1.8 KV/m

We know that

Electric potential difference ΔV given as

ΔV = E .d

Here

E= 1.8 KV/m

d= 3.6 m

ΔV = E .d

ΔV = 1.8 x 3.6 KV

ΔV = 6.48 KV

Given that

q=+2.90 µC

Change in electric potential energy ΔU given as

ΔU = q .ΔV

$\Delta U=2.9\times 10^{-6}\times 6.48\times 10^3\ J$

ΔU =18.79 mJ

8 0

3 years ago