Specific heat capacity= heat energy/mass×temperature rise
962°C - 20°C = 942K
Heat energy (Eh) = 239 × 1.55 × 942
Eh= 348963.9J
shc of Ag: 238.6 J/kg-K
m of Ag: 1.55kg
Given:
Circumference = 2 m
Angular speed, ω = 1 rev/s = 2π radians/s
If the radius is r, then
2πr = 2
r = 1/π m
The linear (tangential) speed is
v = rω
= (1/π m)*(2π rad/s) = 0.5 m/s
Answer: 0.5 m/s
Answer:
The rate of angle is 26.25 rad/sec.
Explanation:
Given that,
First side of triangle a= 20 cm
Second side of triangle b= 50 cm
One side of a triangle is increasing at a rate = 5 cm/sec
Second side is increasing at a rate = 7 cm/s
Angle
If the area of the triangle remains constant,
We need to calculate rate of angle
Using formula of area of triangle

On differentiating

Put the value into the formula



Hence, The rate of angle is 26.25 rad/sec.
Answer:
<h2>velocity =25</h2>
Explanation:
<h3>Average velocity =total displacement <em>/</em><em>time </em><em>e </em><em>taken</em></h3>
<em>so,</em><u>average </u><u>velocity</u><u> </u><u>=</u><u>total </u><u>displacement</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>total </u><u>time </u>taken
100m/4 =25
<h2>
velocity =25</h2>
Its c). cause they are separate variables