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Marat540 [252]
3 years ago
13

A substance with a define shape and volume is a

Physics
1 answer:
Vlad1618 [11]3 years ago
8 0
Solid is the answer.
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A snowmobile has an initial velocity of 3.0 m/s
dexar [7]
My answer to the problem is as follows:
 
<span>1. Use the kinematic formula 

Vf = Vi + a*t 

for a, Vi = 3.0 m/s, a = 0.5 m/s/s, and t = 7.o s. 

for b, Vf = 0, Vi = 3.0 m/s, and a = -0.60 m/s/s. 

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
7 0
2 years ago
Read 2 more answers
The length of the mercury thread is found to be 4cm and 24cm at ice point and steam point respectively on an ungraduated thermom
BabaBlast [244]

Answer:

The difference between ice and steam in Celsius (Centigrade) is 100 deg.

So the difference between and 4 cm and 24 cm of the thread corresponds to 100 deg C.

So 8 cm is 4 cm greater than the ice point

4 cm / 20 cm = 1/5     since the steam point and the ice point are 20 cm apart

Then 1/5 * 100  deg C = 20 deg C   the requested temperature

6 0
3 years ago
Write a collision scenario here. If you choose your own collision, you can have neither, one, or both of the objects break. Be s
OleMash [197]

Answer:

My scenario would be A Car vs. a guard rail on a road.  You have a car that is coming down a Highway at a speed of 43 Mph Miles per hour (69.2018 Kmh)

And it hits a steel guardrail and the car smashes in at the front and the guardrail is only bent while the car has the bumper and the hood along with the headlights and windshield along with the passenger side window break.

Explanation:

This is caused by so much force reacting from one object to another but also depends on molecular density.

5 0
2 years ago
A large crane consists of a 20 m, 3,000 kg arm that extends horizontally on top of a vertical tower. The arm extends 15 m toward
Anni [7]

Answer:

m=18000kg

Explanation:

From the question we are told that:

Crane Length l=20m

Crane Mass m_a=3000kg

Arm extension at lifting end l_l=15m

Arm extension at counter weight end l_c=5m

Load M_l=5000kg

Generally the equation for Torque Balance is mathematically given by

T_1 *l_c-(m_a*g) *l_c-(T_2)*l_l=0

mg*5 *-(3000*9.8) *5-(5000*9.8)*15=0

m=18000kg

7 0
3 years ago
A spring of spring constant 25 N/m is hung vertically and a 0.300 kg mass is attached to one end, causing a displacement of the
Mamont248 [21]

Answer:k=1175

Explanation:thank  you for asking

3 0
3 years ago
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