Answer: The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the remaining electron in the 3s. Therefore the sodium electron configuration will be 1s22s22p63s1.
Explanation:
Use a colander and sake the water out
Answer:

Explanation:
Assume the reaction is the combustion of propane.
Word equation: propane plus oxygen produces carbon dioxide and water
Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)
Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)
(a) Table of enthalpies of formation of reactants and products

(b)Total enthalpies of reactants and products

ΔᵣH° is negative, so the reaction is exothermic.
52
Explanation:
We need to understand and apply the rules of significant figures when carrying out addition operations to solve this problem:
Rules of significant figures:
- Non-zero digits are always significant in a given number
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion is significant.
- Any leading zero in a decimal is significant.
In addition, the answer of the sum is given to the least number of significant digits of the given numbers:
44.2124
+ 0.81
+ 7.335
sum 52.3574
Now the least number of significant figure is 2 as seen in 0.81
we round the sum up to 52
learn more:
Significant numbers brainly.com/question/6384538
#learnwithBrainly
Explanation:
electrovalent bond covers single bond.
Covalent bond covers double or more bonds.