A uniform diving board, 12 meters long and 20 kg in mass, is hinged at P, which is 5 meters from the edge of the platform. An 80
kg diver is standing at the other end of the board. hinge 1. The force exerted by the hinge on the board will be very nearly a) 1000 N upward b) 1080 N upward c) 1080 N downward d) 1160 N upward e) 1160 N downward 2. The normal force on the board at the edge of the platform will be a) 2160 N b) 1000N c) 200 N d) 160 N e) 60 N
1 answer:
You might be interested in
The final velocity of the two pucks is -5 m/s
Explanation:
We can solve the problem by using the law of conservation of momentum.
In fact, in absence of external force, the total momentum of the two pucks before and after the collision must be conserved - so we can write:
where
is the mass of each puck
is the initial velocity of the 1st puck
is the initial velocity of the 2nd puck
v is the final velocity of the two pucks sticking together
Re-arranging the equation and solving for v, we find:
Learn more about momentum:
#LearnwithBrainly