A uniform diving board, 12 meters long and 20 kg in mass, is hinged at P, which is 5 meters from the edge of the platform. An 80
kg diver is standing at the other end of the board. hinge 1. The force exerted by the hinge on the board will be very nearly a) 1000 N upward b) 1080 N upward c) 1080 N downward d) 1160 N upward e) 1160 N downward 2. The normal force on the board at the edge of the platform will be a) 2160 N b) 1000N c) 200 N d) 160 N e) 60 N
1 answer:
You might be interested in
Answer:
60 km
Explanation:
For an object (or a person, such as in this case) moving at constant speed, the speed is equal to the ratio between the distance travelled and the time taken:
where
v is the speed
d is the distance
t is the time taken
In this case, we have:
v = 120 km/h is the speed
t = 30 min = 0.5 h is the time taken
Therefore, we can rearrange the equation to find the total distance travelled: