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2 years ago

______ interference occurs when two waves are out of phase.

Physics

1 answer:

Otrada [13]2 years ago

5 0

Answer:

What interference occurs when two waves are out of phase?

Image result for ______ interference occurs when two waves are out of phase.

Destructive interference

Destructive interference occurs when the maxima of two waves are 180 degrees out of phase: a positive displacement of one wave is canceled exactly by a negative displacement of the other wave. The amplitude of the resulting wave is zero.

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Two dogs are pulling a disk, but the disk is not moving. The disk does not move because the forces are (select one: unbalanced,

tiny-mole [99]

Answer:

balanced?

Explanation:

because if it wasn't moving that means they are pulling at a similar strength

8 0

3 years ago

Read 2 more answers

A 328-kg car moving at 19.1 m/s in the x direction hits from behind a second car moving at 13.0 m/s in the same direction. If th

Jet001 [13]

Answer:

14.04 m/s

Explanation:

To find the velocity of the first car after the collision, we can use the equation of conservation of momentum:

m1v1 + m2v2 = m1'v1' + m2'v2'

We have the following data:

m1 = m1' = 328,

m2 = m2' = 790,

v1 = 19.1,

v2 = 13,

v2' = 15.1.

Using this data, we can find v1' (final velocity of the first car):

328 * 19.1 + 790 * 13 = 328 * v1' + 790 * 15.1

16534.8 = 328 * v1' + 11929

328 * v1' = 4605.8

v1' = 14.04 m/s

3 0

3 years ago

The perihelion of the comet TOTAS is 1.69 AU and the aphelion is 4.40 AU. Given that its speed at perihelion is 28 km/s, what is

dybincka [34]

Answer:

The speed at the aphelion is 10.75 km/s.

Explanation:

The angular momentum is defined as:

$L = mrv$ (1)

Since there is no torque acting on the system, it can be expressed in the following way:

$t = \frac{\Delta L}{\Delta t}$

$t \Delta t = \Delta L$

$\Delta L = 0$

$L_{a} - L_{p} = 0$

$L_{a} = L_{p}$ (2)

Replacing equation 1 in equation 2 it is gotten:

$mr_{a}v_{a} =mr_{p}v_{p}$ (3)

Where m is the mass of the comet, $r_{a}$ is the orbital radius at the aphelion, $v_{a}$ is the speed at the aphelion, $r_{p}$ is the orbital radius at the perihelion and $v_{p}$ is the speed at the perihelion.

From equation 3 v_{a} will be isolated:

$v_{a} = \frac{mr_{p}v_{p}}{mr_{a}}$

$v_{a} = \frac{r_{p}v_{p}}{r_{a}}$ (4)

Before replacing all the values in equation 4 it is necessary to express the orbital radius for the perihelion and the aphelion from AU (astronomical units) to meters, and then from meters to kilometers:

$r_{p} = 1.69 AU x \frac{1.496x10^{11} m}{1 AU}$ ⇒ $2.528x10^{11} m$

$r_{p} = 2.528x10^{11} m x \frac{1km}{1000m}$ ⇒ $252800000 km$

$r_{a} = 4.40 AU x \frac{1.496x10^{11} m}{1 AU}$ ⇒ $6.582x10^{11} m$

$r_{p} = 6.582x10^{11} m x \frac{1km}{1000m}$ ⇒ $658200000 km$

Then, finally equation 4 can be used:

$v_{a} = \frac{(252800000 km)(28 km/s)}{(658200000 km)}$

$v_{a} = 10.75 km/s$

Hence, the speed at the aphelion is 10.75 km/s.

8 0

3 years ago

Which of these chemical equations demonstrates the law of conservation of mass as it applies to the combustion of ethane? A. 2 C

WINSTONCH [101]

A. 2 C₂ H₆ + 7 O₂ → 4 C O₂ + 6 H₂ O

according to law of conservation of mass , the total mass of reactants side must be same as the total mass of product side. so we need to check if each atom in the equation has same number on both side of the equation or not.

in this equation , we have

4 atoms of carbon left and 4 atoms of carbon on right

12 atoms of hydrogen on left and 12 atoms of hydrogen on right

14 atoms of oxygen on left and 14 atoms of oxygen on right

3 0

4 years ago

Two point charges q1 = 4. 0 µc and q2 = -8. 0 µc are placed along the x-axis at x1 = 0 m and x2 = 0. 20 m, respectively. What is

scoundrel [369]

The electric potential energy of this system of charges will be +1.44 J. Option E is correct.

<h3>What is the electric potential energy ?</h3>

Electric potential energy stands for the energy that is required to displace a charge in against an electric field.

Given data;

q₁ = 4. 0 µc

q₂ = -8. 0 µc

D(distance between charges) = 0.2 m

The electric potential energy is found as;

$\rm E = \frac{Kq_1q_2}{r} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6}\times (-8.0)\times 10^{-6}}{0.2} \\\\ E=+1.44 J$

The electric potential energy of this system of charges will be +1.44 J.

Hence,option E is correct.

To learn more about the electric potential energy refer:

brainly.com/question/12645463

#SPJ4

5 0

2 years ago