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Oksana_A [137]
2 years ago
9

Guillaume Amontons first took a stab at measuring absolute zero in 1702. What would be the most reasonable way it would have bee

n done then?
A) Measure the pressure of a gas in a container at various temperatures, say from 100 °C down to maybe −20 °C, then extrapolate to the temperature at which the pressure would reach zero.
B) Measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops.
C) Measure the pressure of a gas and cool it until the pressure is zero.
Physics
1 answer:
Oliga [24]2 years ago
4 0

He would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops.

<h3>What is the absolute zero?</h3>

The absolute zero refers to the temperature at which the gas seems to stop moving. Recall that temperature is the measure of the average kinetic energy of the molecules of a gas.

Hence, if Guillaume Amontons first took a stab at measuring absolute zero in 1702, he would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops.

Learn more about absolute zero:brainly.com/question/27951132

#SPJ1

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In order to solve this problem it is necessary to apply the concepts related to intensity and specifically described in Malus's law.

Malus's law warns that

I = I_0 cos^2\theta

Where,

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I_0 =Intensity of the light before passing through the polarizer

The intensity of the beam from the first polarizer is equal to the half of the initial intensity

I = \frac{I_0}{2}

Replacing with our the numerical values we get

I = \frac{46}{2}

I = 23W/m^2

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3 years ago
A car has a uniform velocity of 108km/h. How far does it travel in 30 seconds?​
natita [175]
  • Velocity=108km/h

Convert to m/s

\\ \tt\longmapsto 108\times \dfrac{5}{18}

\\ \tt\longmapsto 30m/s

  • Time=30s.

\\ \tt\longmapsto Distance=Velocity\times Time

\\ \tt\longmapsto Distance=30(30)

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You are at rest with respect to the car.
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An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standar
defon

Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

The power output W = 2 MW

Efficiency \zeta = 3%

where;

\zeta = \dfrac{W_{out}}{Q_{supplied }}

Q_{supplied } = \dfrac{2}{0.03} \ MW

Q_{supplied } = 66.66 \ MW

However, from the evaporator, the heat transfer Q can be determined by using the formula:

Q = UA(L MTD)

where;

LMTD = \dfrac{\Delta T_1 - \Delta T_2}{In (\dfrac{\Delta T_1}{\Delta T_2} )}

Also;

\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K

\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K

LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}

LMTD = \dfrac{8}{In (5)}

LMTD = 4.97

Thus, the required heat exchanger area A is calculated by using the formula:

Q_H = UA (LMTD)

where;

U = overall heat coefficient given as 1200 W/m².K

66.667 \times 10^6 = 1200 \times A \times 4.97 \\ \\  A= \dfrac{66.667 \times 10^6}{1200 \times 4.97} \\ \\  \mathbf{A = 11178.236 \ m^2}

The mass flow rate:

Q_{H} = mC_p(T_{in} -T_{out} )  \\ \\  66.667 \times 10^6= m \times 4.18 (300 -292) \\ \\ m = \dfrac{  66.667 \times 10^6}{4.18 \times 8} \\ \\  \mathbf{m = 1993630.383 \ kg/s}

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Sound energy is produced when an object vibrates so an example would be a telephone ringing or someone playing a bass guitar 
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