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ICE Princess25 [194]
3 years ago
14

Solve the inequality. Then graph your solution. -9v – 10 < 7y +6

Engineering
1 answer:
Cerrena [4.2K]3 years ago
5 0
16

if you add 9+10 you get 18 - 7+6
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Question 5 of 10
Angelina_Jolie [31]

The cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors will be D. 8 cubic inches.

<h3>What is a conductor?</h3>

It should be noted that a conductor simply means a substance or material that simply allows electricity to pass through it.

From the information given, the cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors is yo be computed.

This will be:

= (4 × 6)/3

= 24/3

= 8

In conclusion, the cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors will be 8 cubic inches.

Learn more about conductor on:

brainly.com/question/11845176

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6 0
2 years ago
The yield of a chemical process is being studied.The two most important variables are thought to be the pressure and the tempera
anyanavicka [17]

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<u>note:</u>

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7 0
3 years ago
A mass of 5 kg of saturated water vapor at 100 kPa is heated at constant pressure until the temperature reaches 200°C.
Alex73 [517]

Answer: you can watch a video on how to solve this question on you tube

6 0
4 years ago
The objective of a properly proportioned concrete mix are: a.__________________________________________________________ b.______
sukhopar [10]

Answer:

The objective of a properly proportioned concrete mix are:

  • To produce the combination of cementitious material, water, and aggregate that meets the requirements of a particular structure, portion of a structure, or series of structures at least cost.
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4 0
3 years ago
Read 2 more answers
A beaker is filled to the 500 ml mark with alcohol. What increase in volume (in ml) the beaker contain when the temperature chan
Tomtit [17]

Answer:

1.4 mL

Explanation:

Given that:

volume of alcohol V_0 = 500

Temperature change ΔT = (30° - 5°)C

=25° C

\beta_{ alcohol }= 1.12 \times 10^{-4} / ^0C

The increase in volume ΔV =  \alpha  \times  V_o \times \Delta T

= 500 \times 1.12 \times 10^{-4} / ^0 C\times   25^0 C

= 1.4 mL

8 0
3 years ago
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