Answer:All of the above
Explanation:
9.62 psi means 497.49 mm of Hg pressure
for (a)19.58 inches is equals to 497.49 mm of Hg
(b)atmospheric pressure is 14.69 psi
vaccum gauge is 9.62psi
absolute pressure is=14.69-9.62=5.07
(c)vaccum means air is sucked and there is negative pressure so it tells about below atmospheric pressure.
thus all are correct
I think it’s structural engineers but still check with the others
Answer:
Changing oil.
Explanation:
You need to regularly check and change your car’s oil to ensure smooth running of the vehicle and to prolong the lifespan of its engine.
Answer:
![h_{max} = 51.8 cm](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%2051.8%20cm)
Explanation:
given data:
height of tank = 60cm
diameter of tank =40cm
accelration = 4 m/s2
suppose x- axis - direction of motion
z -axis - vertical direction
= water surface angle with horizontal surface
accelration in x direction
accelration in z direction
slope in xz plane is
![tan\theta = \frac{a_x}{g +a_z}](https://tex.z-dn.net/?f=%20tan%5Ctheta%20%3D%20%5Cfrac%7Ba_x%7D%7Bg%20%2Ba_z%7D)
![tan\theta = \frac{4}{9.81+0}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7B4%7D%7B9.81%2B0%7D)
![tan\theta =0.4077](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D0.4077)
the maximum height of water surface at mid of inclination is
![\Delta h = \frac{d}{2} tan\theta](https://tex.z-dn.net/?f=%5CDelta%20h%20%3D%20%5Cfrac%7Bd%7D%7B2%7D%20tan%5Ctheta)
![=\frac{0.4}{2}0.4077](https://tex.z-dn.net/?f=%20%3D%5Cfrac%7B0.4%7D%7B2%7D0.4077)
![\Delta h 0.082 cm](https://tex.z-dn.net/?f=%20%5CDelta%20h%20%200.082%20cm)
the maximu height of wwater to avoid spilling is
![h_{max} = h_{tank} -\Delta h](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%20h_%7Btank%7D%20-%5CDelta%20h)
= 60 - 8.2
![h_{max} = 51.8 cm](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%2051.8%20cm)
the height requird if no spill water is ![h_{max} = 51.8 cm](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%2051.8%20cm)
Answer:
The amplitude of the absorbed mass can be found
for ka:
![X_{a} =0.002m=\frac{F_{0} }{K_{a} } =\frac{250}{K_{a} } =125000N/m](https://tex.z-dn.net/?f=X_%7Ba%7D%20%3D0.002m%3D%5Cfrac%7BF_%7B0%7D%20%7D%7BK_%7Ba%7D%20%7D%20%3D%5Cfrac%7B250%7D%7BK_%7Ba%7D%20%7D%20%3D125000N%2Fm)
now
![w^2=\frac{K_{a} }{m_{a} } \\m_{a} =\frac{K_{a} }{w^2} =\frac{125000}{[6000*2\pi /60]^2} =0.317kg](https://tex.z-dn.net/?f=w%5E2%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bm_%7Ba%7D%20%7D%20%5C%5Cm_%7Ba%7D%20%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bw%5E2%7D%20%3D%5Cfrac%7B125000%7D%7B%5B6000%2A2%5Cpi%20%2F60%5D%5E2%7D%20%3D0.317kg)