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jenyasd209 [6]
3 years ago
12

A south-facing collector at latitude 40◦ is tipped up at an angle equal to its latitude. Compute the following insolations for J

anuary 1st at solar noon:
a. The direct beam insolation normal to the sun’s rays.

b. Beam insolation on the collector.

c. Diffuse radiation on the collector.

d. Reflected radiation on the collector with ground reflectivity 0.2.
Engineering
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

Explanation:

(c). looking for the radiation of the collector is given thus

C = 0.095 + 0.04 sin [360/365(n-100)] = 0.095 + 0.04 sin [360/365(1-100)]

C = 0.05535

∴ Diffuse radiation of the collector Idc = C*Ib + (1+cosσ/2)  

Idc = 0.5535 * 908.7 (1+cos40/ 2) = 44.41 W/m²

Idc = 44.41 W/m²

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Consider a 1.80-m-tall man standing vertically in water and completely submerged in a pool. Determine the difference between the
defon

Answer:

17.658 kPa

Explanation:

The hydrostatic pressure of a fluid is the weight of a column of that fluid divided by the base of that column.

P = \frac{weight}{base}

Also, the weight of a column is its volume multiplied by it's density and the acceleration of gravity:

weight = \delta * v * g

Meanwhile, the volume of a column is the area of the base multiplied by the height:

V = base * h

Replacing:

P = \frac{\delta * base * h * g}{base}

The base cancels out, so:

P = \delta * h * g

The pressure depends only on the height of the fluid column, the density of the fluid and the gravity.

If you have two point at different heights (or depths in the case of objects submerged in water) each point will have its own column of fluid exerting pressure on it. Since the density of the fluid and the acceleration of gravity are the same for both points (in the case of hydrostatics density is about constant for all points, it is not the case in the atmosphere), we can write:

\Delta P = \rho * g * (h1 - h2)

We do not know at what depth the man of this problem is, but it doesn't matter, because we know the difference in height of the two points of interes (h1 - h2) = 1.8 m. So:

\Delta P = 9.81 \frac{m}{s^{2} } * 1000 \frac{kg}{m^3} * 1.8 m = 17658 Pa = 17.658 kPa

4 0
3 years ago
Seawater containing 3.50 wt% salt passes through a series of 11 evaporators. Roughly equal quantities of water are vaporized in
statuscvo [17]

Answer: the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr

Explanation:

F, W and B are the fresh feed, brine and total water obtained

w = 2 x 10^4 L/h

we know that

F = W + B

we substitute

F = 2 x 10^4 + B

F = 20000 + B .................EQUA 1

solute

0.035F = 0.05B

B = 0.035F/0.05

B = 0.7F

now we substitute value of B in equation 1

F = 20000 + 0.7F

0.3F = 20000

F = 20000/0.3

F = 66666.67 kg/hr

B = 0.7F

B = 0.7 * F

B = 0.7 * 66666.67

B = 46,666.669 kg/hr

the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr

8 0
4 years ago
Why why why why why why why
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6 0
4 years ago
Read 2 more answers
Output all combinations of character variables a, b, and c. If a = 'x', b = 'y', and c = 'z', then the output is: xyz xzy yxz yz
gladu [14]

Answer & Explanation:

//written in java

public class Main {

   public static void main(String[] args) {

       //declare a char variable for a, b, c

       char a;

       char b;

       char c;

       //assign a b and c

       //a b and c can be replaced for with  

       // '#', '$', '%', then with '1', '2', '3'

       // for further testing

       a = 'x';

       b = 'y';

       c = 'z';

       //output for all possible combination for a, b, c.

       System.out.println("" + a + b + c + " " + a + c + b + " " + b + a + c +

               " " + b + c + a + " " + c + a + b + " " + c + b + a);

   }

}

7 0
4 years ago
What historical event allowed both aerospace fields to make enormous strides forward?
Lostsunrise [7]

Answer:

The world wars. Especially world War II

Explanation:

The world wars were the single most notable events that led to the leap in development of the aircraft from a simple apparatus capable of flight to a sophisticated flight machine. Airplane production was at its maximum during these periods (especially world war II) and has never seen that capacity of production again since. Countries focused on research that could add even the slightest enhancements to their aircraft in order to for it to surpass that of other countries.

6 0
3 years ago
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