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snow_tiger [21]
2 years ago
14

What is the mass of 5.00 moles of KaS04?

Chemistry
1 answer:
Varvara68 [4.7K]2 years ago
7 0

Answer: D

Explanation:

I assume you meant \text{K}_{2}\text{SO}_{4}.

  • The atomic mass of potassium is 39.0983 g/mol.
  • The atomic mass of sulfur is 32.065 g/mol.
  • The atomic mass of oxygen is 15.9994 g/mol.

So, the formula mass of potassium sulfate is 2(39.0983)+32.065+4(15.9994)=174.2592 g/mol.

So, 5.00 moles have a mass of (5.00)(174.2592), which is about <u>870 g</u>

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NaN₃ is the chemical formula for Sodium Azide
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Thermal energy is the energy an object has due to the _____ of the particles
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Explanation: when particles bounce against each other the friction creates thermal energy. Think about what happens when you rub your hands together and they get warmer, that the friction between your hands making thermal energy.

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3 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
Explain, in terms of electrons, why the radius of a calcium ion is smaller than the radius of a calcium atom.
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3 years ago
What is the pressure of 1.20 moles of SO2 gas in a 4L container at 30 degrees celsius
geniusboy [140]
Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

                                       P V  =  n R T
Solving for P,
                                       P  =  n R T / V     ----- (1)
Data Given;

Moles  = n = 1.20 mol

Volume  = V =  4 L

Temperature  = T = 30 + 273 = 303 K

Gas Constant  = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

                     P  =  (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

                     P  =  7.45 atm
6 0
3 years ago
Read 2 more answers
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