The correct balanced chemical equation which occur when methane burn in oxygen gas is
CH4 + 2O2 --> 2H2O +CO2 (answer D)
when methane is burned in presence of oxygen gas it produces carbon(IV) oxide and water and energy,that is 1 mole of CH4 reacted with 2 moles of O2 to form 2 moles of water and 1 mole of CO2 and enegy. This energy make the methane to be used as fuel.
Answer:
The equilibrium shifts to produce more reactants.
Explanation:
According to the Le- Chatelier principle,
At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.
The equilibrium can be disturb,
By changing the concentration
By changing the volume
By changing the pressure
By changing the temperature
Consider the following chemical reaction.
Chemical reaction:
2SO₂ + O₂ ⇄ 2SO₃
In this reaction the equilibrium is disturb by increasing the concentration of Product.
When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of SO₃ increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.
0.250 L*3M=0.250 L*3mol/L= 0.750 mol
Answer:
When carbon is burned in air, it forms carbon dioxide gas and releases a large amount of heat and some light:
C+O2= CO2+ heat+ light
