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IrinaVladis [17]
3 years ago
5

I need help. It’s due tonight. Thanks

Chemistry
2 answers:
VikaD [51]3 years ago
4 0

Answer:

(a) Streptococcus - Pro

(b) Yeast - Euk

(c) A euglena - Pro

(d) Acidophilus -Pro

shepuryov [24]3 years ago
4 0
All of them are prokaryotes except for yeast because it’s cells have membrane bound nuclei
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Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40
devlian [24]

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

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Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

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ΔT =  40°C -20°C

ΔT =  20°C

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48 J =240 g.°C×c

c = 48 J/240 g.°C

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<span>Oxygen has 8 protons in its nucleus. </span>
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Whats the molar mass of potassium nitride
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