In this kind of exercises, you should use the "ideal gas" rules: PV = nRT
P should be in Pascal:
445mmHg = 59328Pa
1225mmHg = 163319Pa
V should be in cubic meter:
16L = 0.016 m3
R =
= constant
=
==> P1 * V1 = P2 * V2
V2 =
=
V2 = 0.00581 m3 = 5.81 L
M=f/a m=129000N/84m/s/s=1535.714286kg/m/s/s
Answer: What is required on a chemical label includes pictograms, a signal word, hazard and precautionary statements, the product identifier, and supplier identification.
Explanation:
Answer:
Kindly check the explanation section.
Explanation:
Based on the description of the reacting -OH group containing Compound, the drawing of the chemical compound is given in the attached picture.
So, without mincing words let's dive straight into the solution to the question.
The reaction between the OH containing compound and PCC is an oxidation reaction.
Looking at the carbon number 1 which the first OH group and CH3 are attached to. Oxidation can not occur here as tertiary alcohol can not be oxidize.
Hence, the second OH will be oxidized into a carbonyl group, C = O. Kindly note that when alcohol oxidizes it turns into an aldehyde.
The equation for the reaction is also given the the attached picture.
Answer:
d= 50.23 g/cm³
Explanation:
Given data:
radius = 137.9 pm
mass is = 5.5 × 10−22 g
density = ?
Solution:
volume of sphere= 4/3π r³
First of all we calculate the volume:
v= 4/3π r3
v= 1.33× 3.14× (137.9)³
v= 1.33 × 3.14 × 2622362.939 pm³
v= 1.095 × 10∧7 pm³
v= 1.095 × 10∧-23 cm³
Formula:
Density:
d=m/v
d= 5.5 × 10−22 g/ 1.095 × 10∧-23 cm³
d= 5.023 × 10∧+1 g/cm³
d= 50.23 g/cm³
