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2 years ago

Which statement correctly describes the path that an electrical impulse would take after someone touched a hot pot?

Physics

1 answer:

Taya2010 [7]2 years ago

6 0

Answer:

A. The signal travels through the nerve of the hand to the spinal cord and then to the brain.

Explanation:

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A toy racer moves clockwise around a circular track of radius 3 m at a constant speed of 6 m/s. When it is at point A its veloci

Llana [10]

Answer:

2 m/s

Explanation:

divide 6 by 3

3 0

3 years ago

A tiny object carrying a charge of +44 μC and a second tiny charged object are initially very far apart. If it takes 21 J of wor

STatiana [176]

Answer:

The magnitude of the second charge is $\rm 1.062\times 10^{-7}\ C$ or $\rm 0.1062\ \mu C.$

Explanation:

The work done in bringing a charged particle from one point to another in the presence of some electric field is equal to the change in the electric potential energy of the charge in moving from one point to another.

The electric potential energy of some charge $q_o$ at a point in the electric field of another charge $q$ is given by the product of the amount of charge $q_o$ and electric potential at that point due to the charge $q$ .

$U = q_o\ V.$

The electric potential at that point is given by

$V = \dfrac{kq}{r}.$

where $k$ is the Coulomb's constant.

Therefore,

$U=q_o\ \dfrac{kq}{r}.$

Now, We have given two charges $q_1 = +44\ \mu C = +44\times 10^{-6}\ C$ and $q_2$ , whose value is to be found.

When the two charges are infinitely dar apart, the electric potential energy of the system is given by

$U_i = \dfrac{kq_1q_2}{\infty}=0.$

When the coordinates of position of the two charges are

$(x_1,\ y_1) = (1.00\ mm,\ 1.00\ mm).\\(x_2,\ y_2) = (1.00\ mm,\ 3.00\ mm).$

The distance between the two charges is given by

$r=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(1.00-1.00)^2+(3.00-1.00)^2}=2.00\ mm = 2.00\times 10^{-3}\ m.$

The electric potential energy of the charges in this configuration is given by

$U_f = \dfrac{kq_1q_2}{r}\\=\dfrac{(8.99\times 10^9)\times (+44\times 10^{-6})\times q_2}{2.00\times 10^{-3}}\\=1.9778\times 10^8\times q_2.$

The change in the electric potential energy of the system is equal to the work done to bring the system from inifinitely far apart position to given configuration.

Therefore,

$W = U_f-U_i\\21=(1.9778\times 10^8\times q_2)-0\\\Rightarrow q_2 = \dfrac{21}{1.9778\times 10^8}\\=1.062\times 10^{-7}\ C\\=0.1062\times 10^{-6}\ C\\=0.1062\ \mu C.$

6 0

3 years ago

If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, what be

Vlad1618 [11]

Usually, If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, the statement which would best describe what would occur is the last one : The water and the metal's temperatures will reach the same temperature. I choose this one because this is a nice example of how the nature tries to reach the balance. Hope it helps! Regards.

7 0

3 years ago

It takes a truck 3.56 seconds to slow down from 112 km/h to 87.4 km/h. What is its average acceleration?

maxonik [38]

Answer:

option B

−1.92 m/s2

Explanation:

Given in the question,

time took by truck to slow down = 3.56 sec

initial speed of truck = 112 km/h

final speed of truck = 87.4 km/h

1 km/h = 0.277778 m/s

112 = 31.1 m/s

87.4 = 24.28 m/s

Formula use to calculate the acceleration

v - u = at

where v is final speed

u is initial speed

a is acceleration

t is time

plug values in the equation

24.28 - 31.1 = a(3.56)

-6.8 = a(3.56)

a = -6.8 / 3.56

a = -1.9 m/s²

3 0

3 years ago

A laser printer uses a laser beam to “burn” images onto paper. a)True b)False

anastassius [24]

The answer is false because the laser doest burn the images onto the paper.

5 0

3 years ago

Read 2 more answers