Answer:
(a) 4.21 m/s
(b) 24.9 N
Explanation:
(a) Draw a free body diagram of the object when it is at the bottom of the circle. There are two forces on the object: tension force T pulling up and weight force mg pulling down.
Sum the forces in the radial (+y) direction:
∑F = ma
T − mg = m v² / r
v = √(r (T − mg) / m)
v = √(0.676 m (54.7 N − 1.52 kg × 9.8 m/s²) / 1.52 kg)
v = 4.21 m/s
(b) Draw a free body diagram of the object when it is at the top of the circle. There are two forces on the object: tension force T pulling down and weight force mg pulling down.
Sum the forces in the radial (-y) direction:
∑F = ma
T + mg = m v² / r
T = m v² / r − mg
T = (1.52 kg) (4.21 m/s)² / (0.676 m) − (1.52 kg) (9.8 m/s²)
T = 24.9 N
Answer:
hope this helps you're welcome
Answer:
Current will be 81.7 mA
Which is not given in bellow option
Explanation:
We have given capacitance 
Resistance R = 500 ohm
Voltage V = 12 volt
We know that time constant of RC circuit of RC circuit is given by
Time is given as t = 1 sec
We know that current in RC circuit is given by
So current 
Which is not given in the following option
D. This says the path sweeps out equal segments of the elliptical path in equal times (picture a wedge of a pie shaped like an oval)
Answer:
A=ACCELERATION = -4 m/s^2
B=DISTANCE= 72 m
Explanation:
Solving for the acceleration of the car
A= (10 m/s-30 m/s) / 5s
A= -20 m/s / 5s
A= -4 m/s^2
Solving for the distance traveled after the third second
D= v1 * t + 1/2at^2
D= 30 m/s * 3 s + -2m/s^2 * (3s)^2
D= 90 m + - 18 m
D = 72 m
