20.06 g of Hg and 1.6 g of O₂
<u>Explanation:</u>
To Find:
Number of Mercury and oxygen that can be obtained from 21.7 g of HgO
First we have to write the balanced equation for the decomposition reaction of Mercury(II) oxide as,
2 HgO (s) → 2Hg(l) + O₂ (g)
21.7 g of HgO = 
= 0.1 mol of HgO.
As per the above equation, we can find the mole ratio between HgO and Hg is 1: 1 and that of HgO and oxygen is 2:1 .
So amount of Hg produced = 0.1 mol × 200.59 g / mol ( molar mass of Hg)
= 20.06 g of Hg
Amount of oxygen produced = 0.05 mol × 32 g/ mol = 1.6 g of O₂
Thus it is clear that 20.06 g of Hg and 1.6 g of O₂ is obtained from 21.7 g of HgO
Answer:
b
Explanation:
[H3O+] = 10-pH = 10-3.4 ≅ 3.981 x 10^-4 moles/liter
Answer:
Polyatomic Ionic Compound
Explanation:
In given statement the compound given is called as Sodium oleate this means that when Oleic acid is treated with NaOH then it forms.
In chemistry there are few species which are involved in the formation of compounds.
(i) Atoms:
It is very common that atoms of different elements combine to form compound through covalent bond. For example, H₂, O₂, N₂, F₂ e.t.c.
(i) Ions:
Other than covalent compounds we have ionic compounds. Ionic compounds are made up of ions. These ions forming the ionic compounds can be monatomic like Na⁺, Br⁻, Mg²⁺, Al³⁺, N⁻³ or they can be polyatomic like CO₃²⁻, SO₄²⁻, NH₄⁺, PO₄³⁻ e.t.c.
(iii) Polyatomic Ions:
In polyatomic ions we find a charge on a molecule which contains two or more atoms bonded covalently. Hence, in given compound we have a long chain of molecule containing a negative charge neutralized by opposite +ve charged sodium ion. Hence, Sodium oleate is a polyatomic ionic compound.
1. <em>Increasing the concentration of one or more reactants will often increase the rate of reaction. This occurs because a higher concentration of a reactant will lead to more collisions of that reactant in a specific time period. </em>
<em>2. Physical state of the reactants and surface area.</em>
