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Harman [31]
2 years ago
8

calculate the weight of an object of mass 100 kg on the surface of a Planet whose mass and diameter are 4.8*10^24 kg and 12000km

respectively.​
Physics
1 answer:
PilotLPTM [1.2K]2 years ago
6 0

The weight of an object mass of 100 kg on the surface of a Planet willl is 981 N.

<h3>What is weight?</h3>

The weight of matter is found as the product of the mass and the gravitational acceleration;

Given data;

Weight of an object,W =?

Mass,m = 100 kg

\rm W= mg \\\\ \rm W= 100  \ kg  \times 9.81 \ m/sec^2 \\\\ W=981 \ N

Hence the weight of an object willl be 981 N.

To learn more about the weight refer;

brainly.com/question/10069252

#SPJ1

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KIM [24]

Answer:

A) B = 0.009185 T

B) Drection is negative y-direction

Explanation:

A) We are given;

Speed(v) = 2.5 x 10^(7) m/s

Acceleration (a) = 2.2 x 10^(13) m/s²

We also know that charge of proton(q) = 1.6 x 10^(-19)

Mass of proton(m) = 1.67 x 10^(-27)

Now, Since the proton is moving by circular motion, this force is equal to the centripetal force which is given as;

F = qvBsinθ = ma

Since perpendicular, θ = 90°

And so, sinθ = sin 90 = 1

Thus, qvB = ma

Making B the subject gives;

B = ma/qv

B = (1.67 X 10^(-27) X 2.2 X 10^13)) / (1.6 X 10^(-19) X 2.5 X 10^(7))

= 0.009185 T

B) By use of Flemings right hand rule, we can see that the middle finger points toward negative y-direction, so the magnetic field is in the negative y-direction

4 0
4 years ago
Read 2 more answers
A charge of +3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energ
Marat540 [252]

Answer:

Work done = 4584.9 J

Explanation:

given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C

Solution:

Formula for the potential difference at the center of the circle

P.E = K × q1 q2 /r   (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)

P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C /  0.20 m

P.E =  4584.9 J = Work done

3 0
3 years ago
F1=160N east and F2=50N west, if the acceleration of the object is 3.5 m/s2 what is the mass of the object?
Svetlanka [38]
The mass of the object is the answer of your question

6 0
4 years ago
An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its
Sidana [21]
Internal energy, U, is equal to the work done or by the system, plus the heat of the system: <span>ΔU=q+w
</span>in the question they tell you the work done by the system, and the internal energy:
8185 J= -346 J + q work is negative because it was done BY the system.
substitute in: <span>q=m∗Cp∗ΔT</span> and solve for <span>Cp</span><span>.
</span>
-------------------------------------
remember that <span>ΔT=<span>Tf</span>−<span>Ti
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so the equation, really, is: <span>q=m∗Cp∗(<span>Tf</span>−<span>Ti</span>)</span><span>
------------------------------------------
</span>
<span>185J=−346J+[m∗Cp∗(<span>Tf</span>−<span>Ti</span>)]

</span>plug in the rest of your values and solve for <span><span>Cp</span></span>
4 0
3 years ago
A 7.5 kg block is placed on a table. If it's bottom surface area is 0.6m2, how much pressure does the block exert on the tableto
kap26 [50]
Pressure is defined as the force per unit area. This measurement is more convenient to use for describing a force exerted. The standard unit for pressure is Pascal. For this problem, force is the gravitational pull from the block. Calculations are as follows:

P = F/A where F = mg

F = 7.5 ( 9.81) = 73.6 N

<span>P = 73.6 N / 0.6 m^2 = </span><span>122.5 Pa

Thus, the answer is D.
</span>
7 0
3 years ago
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