Internal energy, U, is equal to the work done or by the system, plus the heat of the system:
<span>ΔU=q+w </span>in the question they tell you the work done by the system, and the internal energy:
8185 J= -346 J + q work is negative because it was done BY the system.
substitute in: <span>q=m∗Cp∗ΔT</span> and solve for <span>Cp</span><span>. </span> ------------------------------------- remember that <span>ΔT=<span>Tf</span>−<span>Ti </span></span> so the equation, really, is: <span>q=m∗Cp∗(<span>Tf</span>−<span>Ti</span>)</span><span>
------------------------------------------ </span> <span>185J=−346J+[m∗Cp∗(<span>Tf</span>−<span>Ti</span>)]
</span>plug in the rest of your values and solve for <span><span>Cp</span></span>
"<span>There can only be one voltage supplied" is the statement among the statements given in the question that true regarding DC current. The correct option among all the options that are given in the question is the second option or option "B'. I hope the answer comes to your help.</span>
