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Nookie1986 [14]
3 years ago
9

A charge of +3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energ

y is required to bring a charge of 25mC from infinity to the center of the circle?
Physics
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

Work done = 4584.9 J

Explanation:

given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C

Solution:

Formula for the potential difference at the center of the circle

P.E = K × q1 q2 /r   (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)

P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C /  0.20 m

P.E =  4584.9 J = Work done

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3 years ago
An astronaut's training centrifuge has a radius of 4.0m. If it goes round once every 2.5s, calculate the velocity of the end of
alexandr1967 [171]

Answer: 10.048m/s

Explanation:

We know that the radius is r = 4.0m

And for rotating things, the tangential velocity (or the velocity of the end of the centrifuge arm) can be calculated as:

v = r*w

The period is T = 2.5s,

This means that if sin(w*t) describes this situation, we have that:

sin(w*t) = sin(w*(t + T))

and we know that:

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sin(w*(0 + T)) = Sin(w*T) = 0

this means that w*T = 2*pi

w = 2*pi/T = 2*pi/2.5s = (2*3.14)/2.5 s = 2.512 hz

Then the velocity can be calculated as

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If the horse lifts a 50 kilogram mass a vertical distance of 3 meters in 2 seconds, what is the horse’s minimum power output?
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Answer:

735watts

Explanation:

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Given

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Answer:

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