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2 years ago

The graph shows f(x)=(1/2)and its translation, g(x).

Mathematics

1 answer:

san4es73 [151]2 years ago

6 0

The translation of four units up describes the transform function g(x) option first is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The question is:

The graph shows f(x)=(1/2)ˣ and its translation, g(x).

Which describes the translation of f(x) to g(x)?

Translation of four units up
Translation of five units up
Translation of four units to the right
Translation of five units to the right

The graph is attached please refer to the picture.

We have the equation of the function f(x):

$\rm f(x) = (\dfrac{1}{2})^x$

From the graph, we can see the graph of the function f(x) is shifted up 4 units because the y-intercept of the graph g(x) is (0, 5)

g(x) = f(x) + 4

$\rm g(x) = (\dfrac{1}{2})^x + 4$

Thus, the translation of four units up describes the transform function g(x) option first is correct.

Learn more about the function here:

brainly.com/question/5245372

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17. Which of the following equations would graph a line parallel to 3y = x + 5? (

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The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st

Step-by-step explanation:

Parallel lines have same slopes and different y-intercepts

To find which equation would graph a line parallel to 3y = x + 5

1. Put the equation in the form of y = mx + c

2. m is the slope of the line and c is the y-intercept

3. Look for the equation which has the same values of m and different

values of c

∵ 3y = x + 5

- Divide each term of the equation by 3 to put the equation in the

form of y = mx + c

∴ y = $\frac{1}{3}$ x + $\frac{5}{3}$

∴ m = $\frac{1}{3}$

∴ c = $\frac{5}{3}$

The first answer:

∵ 3y = x + 1

- Divide each term of the equation by 3

∴ y = $\frac{1}{3}$ x + $\frac{1}{3}$

∴ m = $\frac{1}{3}$

∴ c = $\frac{1}{3}$

∵ The two equations have same slope m = $\frac{1}{3}$

∵ The two equations have different y-intercepts c = $\frac{5}{3}$

and c = $\frac{1}{3}$

∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5

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