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DiKsa [7]
3 years ago
13

_______ do not have definite size or always take the shape of their container?

Physics
2 answers:
rewona [7]3 years ago
8 0
Either Liquids or Gass 
amid [387]3 years ago
6 0
Liquids do not have a definite size and always take the shape of the container they're in.

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When does the mechanical energy of a body falls freely equal twice its potential energy ?
Ilia_Sergeevich [38]
<span>As the body rises up its gravitational potential energy increases but its kinetic energy decreases.

As a body falls its gravitational potential energy decreases but it's kinetic energy increases</span>
4 0
3 years ago
5
e-lub [12.9K]
It’s 50 I did the math.
3 0
2 years ago
A painter lifts a 2.8 kg bucket using a rope. if the acceleration of the bucket in 3.1 m/s2, what is the tension in the rope (in
ad-work [718]
Refer to the diagram shown below

Given:
m = 2.8 kg, the mass of the bucket
a =3.1 m/s², the acceleration of the bucket
Therefore
W = 2.8*9.8 = 27.44 N, the weight of the bucket.

Let T =  the tension in the rope.

From the free body diagram, the net force accelerating the bucket is
T - W = m*a
That is,
T = W + m*a
   = 27.44 + 2.8*3.1 N
   = 36.12 N

Answer:  d. 36.1 N

7 0
3 years ago
Read 2 more answers
Years ago, a block of ice with a mass of about 20.0 kg was used daily in a home icebox. The temperature of the ice was 0.0°C whe
m_a_m_a [10]

Answer: The ice absorb 6671.1 kJ of thermal energy.

Explanation:

The conversions involved in this process are :

0.00^0C=273K

:H_2O(s)(273K)\rightarrow H_2O(l)(273K)

Now we have to calculate the enthalpy change.

\Delta H=n\times \Delta H_{fusion}

where,

\Delta H = enthalpy change = ?

m = mass of ice = 20.0 kg  = 20.0\times 10^3g    (1kg=1000g)

n = number of moles of ice= \frac{\text{Mass of ice}}{\text{Molar mass of water}}=\frac{20.0\times 10^3g}{18g/mole}=1.11\times 10^3mole

\Delta H_{fusion} = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

Now put all the given values in the above expression, we get

\Delta H=1.11\times 10^3mole\times 6010J/mole

\Delta H=6671100J=6671.1kJ     (1 kJ = 1000 J)

Therefore, the enthalpy change is,  6671.1 kJ

6 0
3 years ago
The third-order bright fringe of 610-nm light is observed at an angle of 31° when the light falls on two narrow slits. How far a
Anna11 [10]

Answer:

The distance between the slits is 3.55 μm

Explanation:

Given that,

Order number = 3

Wave length = 610 nm

Angle = 31°

We need to calculate the distance between the slits

Using formula of distance of slit

d\sin\theta=n\lambda

d=\dfrac{n\lambda}{\sin\theta}

Where, n = order number

\lambda= wavelength

Put the value into the formula

d=\dfrac{3\times610\times10^{-9}}{\sin31}

d=3.55\times10^{-6}\ m

d= 3.55\ \mu m

Hence, The distance between the slits is 3.55 μm.

8 0
3 years ago
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