Answer:
188 A
Explanation:
Parameters given:
Length of cable, L = 0.78 m
Angle, θ = 60º
Magnetic field, B = 5.5 * 10^(-5) T
Force experienced by wire, F = 7 * 10^(-3) N
The force experienced by a current carrying wire of length L, due to a magnetic field B is given as:
F = I * L * B * sinθ
=> I = F/(L * B * sinθ)
I = (7 * 10^(-3)) / (0.78 * 5.5 * 10^(-5) * sin60)
I = 188 A
Gs*rs^2 = gm*rm^2
<span>rm = rs*√gs/gm </span>
<span>rm = 6370*√9.83/(9.83-0.009) = 6372.92 </span>
<span>mountain observatory is placed at an altitude worth 2920 m asl
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The sentence can be completed as follows:
"Electricity is the movement of charges from one atom to another along a conductor."
The movement of the the charges is due to the presence of a potential difference across the conductor, which pushes the charges. More specifically, in normal conductors, the carriers of electricity are the electrons. Therefore we can rewrite the sentence as
"Electricity is the movement of electrons from one atom to another along a conductor."
<u>Answer:</u> The Young's modulus for the wire is 
<u>Explanation:</u>
Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.
The equation representing Young's Modulus is:

where,
Y = Young's Modulus
F = force exerted by the weight = 
m = mass of the ball = 10 kg
g = acceleration due to gravity = 
l = length of wire = 2.6 m
A = area of cross section = 
r = radius of the wire =
(Conversion factor: 1 m = 1000 mm)
= change in length = 1.99 mm = 
Putting values in above equation, we get:

Hence, the Young's modulus for the wire is 
Answer:
Explanation:
Option a is correct
If puck and pick constitute a system then the momentum of the system is conserved but not this may not be valid for the puck .
Option e is correct
If puck and pick is the system then momentum is conserved but because of the presence of friction, mechanical energy is not conserved.
Friction will cause the energy to dissipate in heat.