Question

When sulfur burns in air, it forms sulfur dioxide as shown by the equation below.what volume of SO2 is produced when 2.35 g of sulfur burns?
$S(s)+O_{2}(g)=SO_{2}(g)$

Answer 1

1.64 L of sulfur dioxide (SO₂)

Explanation:

We have the following chemical reaction:

S (s) + O₂ (g) → SO₂ (g)

First we calculate the number of moles of sulfur (S):

number of moles = mass / molar weight

number of moles of sulfur = 2.35 / 32 = 0.0734 moles

Looking at the chemical reaction we see that 1 moles of sulfur (S) produces 1 moles of sulfur dioxide (SO₂), so 0.0734 moles of sulfur will produce 0.0734 moles of sulfur dioxide (SO₂).

To calculate the volume of sulfur dioxide (SO₂), assuming that the sulfur dioxide is behaving as an ideal gas and the we determine the gas volume under standard temperature and pressure conditions, we use the following formula:

number of moles = volume / 22.4 (L/mole)

volume = number of moles × 22.4

volume of SO₂ = 0.0734 × 22.4 = 1.64 L

Learn more about:

molar volume

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PS: I appreciate that you took the time and effort to write the chemical equation in a readable way. This makes the question to be very rare :D