1.64 L of sulfur dioxide (SO₂)
Explanation:
We have the following chemical reaction:
S (s) + O₂ (g) → SO₂ (g)
First we calculate the number of moles of sulfur (S):
number of moles = mass / molar weight
number of moles of sulfur = 2.35 / 32 = 0.0734 moles
Looking at the chemical reaction we see that 1 moles of sulfur (S) produces 1 moles of sulfur dioxide (SO₂), so 0.0734 moles of sulfur will produce 0.0734 moles of sulfur dioxide (SO₂).
To calculate the volume of sulfur dioxide (SO₂), assuming that the sulfur dioxide is behaving as an ideal gas and the we determine the gas volume under standard temperature and pressure conditions, we use the following formula:
number of moles = volume / 22.4 (L/mole)
volume = number of moles × 22.4
volume of SO₂ = 0.0734 × 22.4 = 1.64 L
Learn more about:
molar volume
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PS: I appreciate that you took the time and effort to write the chemical equation in a readable way. This makes the question to be very rare :D
