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frozen [14]
3 years ago
13

An oscillator consists of a block of mass 0.500 kg connected to a spring. When set into oscillation with amplitude 35.0 cm, the

oscillator repeats its motion every 0.500 s. Find the (a) period, (b) frequency, (c) angular frequency, (d) spring constant, (e) maximum speed, and (f) magnitude of the maximum force on the block from the spring.
Physics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

a. t=0.5s

b. f=2Hz

c. w =4π

d. k =  78.95 N/m

e. v = 4.39 m/s

f. Fs=4.835N

Explanation:

a. The period of the motion is

t= 0.5 s

b. Frequency

f =1 / t

f = 1 / 0.5 = 2 Hz

c. Angular frequency

w = 2π*f

w = 2π*2Hz= 4π

d. The spring constant is

f = 1/2π * √k/m

k = (2π * f)^2*m =(2π*2Hz)^2 * 0.5 kg

k =  78.95 N/m

e. Maximum speed

Kinetic energy and spring energy to find the maximum speed

1/2 *K*x^2=1/2*m*v^2

1/2 * 78.95N/m*(0.35m)^2=1/2*0.5kg*v^2

Solve to v'

v = 4.39 m/s

f. The maximum force on the block from the spring

Fs= 1/2*K*x^2

Fs=1/2*78.95N/m*(0.35m)^2

Fs=4.835N

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

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b

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Complete Question:

Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:

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D.

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