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Volgvan
2 years ago
13

Every spring has an equilibrium position. Which statements describe a spring at its equilibrium position? Check all that apply.

Chemistry
1 answer:
rjkz [21]2 years ago
8 0

The statements describe a spring at its equilibrium position is the elastic potential energy is zero, the displacement of the spring is at a maximum and the net force acting on the spring is zero.

<h3>What is the equilibrium position?</h3>

A body is in equilibrium when the sum of all forces acting on it equals zero. According to Newton's First Law, when resulting from the laws that act on a body that remains in a state of restriction or in motion in its motion, it remains uniformly null.

In this case the only statements that match the definition of equilibrium position are:

  • The elastic potential energy is zero.
  • The displacement of the spring is at a maximum.
  • The net force acting on the spring is zero.

See more about equilibrium position at brainly.com/question/10374921

#SPJ1

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when propene gas (C3H6) is added to bromine liquid, another liquid is produced which has the formula C3H6Br2. what is the chemic
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Answer:

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Explanation:

The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:

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We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.

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3 years ago
Three blocks of metal at the same temperature are placed on a hot stove. Their specific heat capacities are listed below.Rank th
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Answer:

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Explanation:

Hello,

Since the heat capacity accounts for the required heat to increase by 1°C, 1 kg of the metal, copper is the one that has the lower heat capacity, it means that it requires the least amount of energy to warm up (increase its temperature), this could be substantiated via the mathematical definition of heat capacity:

H=mC(T_2-T_1)

Solving for T_2:

T_2=T_1+\frac{H}{mC}

It means that the lower the heat capacity, the higher the final temperature.

Best regards.

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