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bixtya [17]
2 years ago
15

Look at the above table.

Chemistry
1 answer:
MariettaO [177]2 years ago
7 0

Answer:

<em> 1</em>. A. 0

<em>2</em>. B. 7

<em>3. </em>C<em>.</em><em> </em>4

Explanation:

1. charge is equal to the number of protons minus the number of electrons!

2. neutrons is equal to mass number minus atomic number!

3. valence electrons equal 4!

Hope this helped you! :)

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Position always is relative to another object or location <br> options: True False
-Dominant- [34]

Answer:

True

Explanation:because of the motion

4 0
2 years ago
How does the electron arrangement change moving vertically down a group?​
vampirchik [111]

Answer:

Electrons arrangement change is almost constant down the group, hence nuclear charge is almost constant.

But the energy levels on which electrons are arranged increase down the group, hence shielding or screening effect increases.

6 0
2 years ago
Now, Johnny the pool guy must add enough Na2CO3 to get the pH back up to 7.60. How many grams of Na2CO3 does Johnny need to add
vaieri [72.5K]

Answer:

m = 3.4126 g

Explanation:

First, the question is incomplete but I already put in the comments the rest of the question.

Let's solve the first two questions, and then the actual question you are asking here to give you a better explanation of how to do it.

1) We need the volume of the pool, in this case is easy. Assuming the pool is rectangular, we use the volume of a parallelepiped which is the following:

V = h * d * w

We have the data, but first we will convert the feet to centimeter. This is because is easier to work the volume in cm³ than in feet.

So the height, width and depth of the pool in centimeter are:

h = 32 * 30.48 = 975.36 cm

w = 18 * 30.48 = 548.64 cm

d = 5.3 * 30.48 = 161.54 cm

Now the volume:

V = 975.36 * 548.64 * 161.54

V = 86,443,528.79 cm³ or 86,443,528.79 mL or 86,443.5 L

2) If the pool has a pH of 6.4, the concentration of H+ can be calculated with the following expression:

[H+] = antlog(-pH) or 10^(-pH)

Replacing we have:

[H+] = 10^(-6.4)

[H+] = 3.98x10^-7 M

3) Finally the question you are asking for.

According to the reaction:

Na2CO3 + H+ → 2Na+ + HCO3−

We can see that there is ratio of 1:1 between the H+ and the Na2CO3, so, if we have initially a concentration of 3.98x10^-7 M, the difference between the new concentration of H+ and the innitial, will give the concentration to be added to the pool to raise the pH. Then, with the molecular weight of Na2CO3 (105.98 g/mol) we can know the mass needed.

The new concentration of [H+] is:

[H+] = 10^(-7.6) = 2.58x10^-8 M

The difference of both [H+] will give concentration of Na2CO3 used:

3.98x10^-7 - 2.58x10^-8 = 3.73x10^-7 M

The moles:

moles = 3.73x10^-7 * 86,443.5 = 0.0322 moles

Finally the mass:

m = 0.0322 * 105.98

m = 3.4126 g    

5 0
3 years ago
Our solar system is more than _________ in diameter.
Ksju [112]

My is is big

Because its true our solar system is big

3 0
3 years ago
5. A 4.44 L container holds 0.481 mol of O2 at 22.6°C. What is the pressure of the tank?
mamaluj [8]

Answer:  The pressure of the tank will be 2.63 atm

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = ?

V = Volume of gas = 4.44 L

n = number of moles = 0.481

R = gas constant =0.0821Latm/Kmol

T =temperature =22.6^0C=(22.6+273)K=295.6K

P=\frac{nRT}{V}

P=\frac{0.481mol\times 0.0821Latm/K mol\times 295.6K}{4.44L}=2.63atm

The pressure of the tank will be 2.63 atm

8 0
3 years ago
Read 2 more answers
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