Acceleration = Change in Velocity / time
a = (v - u) / t
Where v = final velocity in m/s
u = initial velocity in m/s
t = time in seconds.
a = acceleration in m/s²
A proper record of the changes in velocity with the corresponding time would help find the acceleration.
Angle α between the velocity of theelectron and the magnetic field of the wire will be 90 degree
Answer:
Take-off velocity = v = 81.39[m/s]
Explanation:
We can calculate the takeoff speed easily, using the following kinematic equation.
where:
a = acceleration = 4[m/s^2]
x = distance = 750[m]
vi = initial velocity = 25 [m/s]
vf = final velocity
![v_{f}=\sqrt{(25)^{2}+(2*4*750) } \\v_{f}=81.39[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3D%5Csqrt%7B%2825%29%5E%7B2%7D%2B%282%2A4%2A750%29%20%7D%20%5C%5Cv_%7Bf%7D%3D81.39%5Bm%2Fs%5D)
Answer:
<h2>
3338.98 kg/m³</h2>
Explanation:
The formula for calculating the relative density of a substance is expressed as
Relative density of a liquid = Density of the liquid /density of water
Given relative density of a liquid = 0.34
Density of water 997kg/m³
Substituting into the formula we have;
Density of the liquid = Relative density of a liquid * density of water
Density of the liquid = 0.34 * 997
Density of the liquid = 3338.98 kg/m³
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