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kow [346]
4 years ago
5

A series of steps that allows someone to conduct an experiment are called a

Physics
1 answer:
ValentinkaMS [17]4 years ago
5 0
Is it the scientific method
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The geologic time scale originally ordered earth’s rocks by
Rasek [7]

The geologic time scale originally ordered Earth’s rocks by relative age.

<u>Explanation:</u>

Geologic time scale is the measure of events occurred in year wise from the starting of universe. Mostly dating of rocks and fossil fuels are doing the trends still now. In order to measure the age of rocks, geological time scale have preferred relative age mode.

In this system, the age of rocks are measured and compared layer by layer. So the lowest layer of rock will be having the maximum age. As we don’t know the starting time of universe, so this method of comparison between the layers to order the rocks is best. So, depending upon the position of the rocks, the age can be determined.

5 0
3 years ago
At locations A and B, the electric potential has the values VA=1.51 VVA=1.51 V and VB=5.81 V,VB=5.81 V, respectively. A proton r
Oksana_A [137]

Answer:

<u>For proton:</u>

A. The proton is released from Vb (highest potential)

B. v = 2.9x10⁴ m/s

<u>For electron:</u>

A. The electron is released from Va (lowest potential)

B. v = 1.2x10⁶ m/s    

Explanation:

<u>For a proton we have</u>:

A. To find the origin from which the proton was released we need to remember that in a potential difference, a proton moves from the highest potential to the lowest potential.                

Having that:

Va = 1.51 V and Vb = 5.81 V

We can see that the proton moves from Vb to Va, hence the proton was released from Vb.

B. We now that the work done by an electric field is given by:

W = \Delta Vq    (1)                                        

Where:

q: is the proton's charge = 1.6x10⁻¹⁹ C    

V: is the potential    

Also, the work is equal to:

W = \Delta K = (K_{a} - K_{b}) = \frac{1}{2}mv_{a}^{2} - \frac{1}{2}mv_{b}^{2}     (2)      

Where:

K: is the kinetic energy

m: is the proton's mass = 1.67x10⁻²⁷ kg

v_{a}: is the velocity in the point a

v_{b}: is the velocity in the point b = 0 (starts from rest)

Matching equation (1) with (2) we have:

\Delta Vq = \frac{1}{2}mv_{a}^{2}

(5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}1.67 \cdot 10^{-27} kg*v_{a}^{2}

v_{a} = 2.9 \cdot 10^{4} m/s

<u>For an electron we have</u>:

A. For an electron we know that it moves from the lowest potential (Va) to the highest potential (Vb), so it is released from Va.

B. The speed is:

\Delta Vq = \frac{1}{2}mv_{b}^{2} - \frac{1}{2}mv_{a}^{2}

Since v_{a} = 0 (starts from rest) and m_{e} = 9.1x10⁻³¹ kg (electron's mass), we have:

(5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}9.1 \cdot 10^{-31} kg*v_{b}^{2}    

v_{b} = 1.2 \cdot 10^{6} m/s

I hope it helps you!

6 0
4 years ago
Short essay your teacher have provided you​
Zinaida [17]
I don’t understand....?
6 0
3 years ago
PLEASE ANSWER! A sound Wave with a frequency of 100.0 Hz travels in water with a speed of 1,500 m/s and then travels in air with
Sedaia [141]

Answer:

ok

Explanation:

12345-7543

8 0
3 years ago
A car engine changes chemical potential energy into the what energy so the car can move
yuradex [85]
It transforms it to mechanical
7 0
3 years ago
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